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3 years ago

Complete the congruence statement by naming the corresponding angle or side. 50 Points

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

4 0

Step-by-step explanation:

Triangles WXY and RPY are congruent.

Since letters X and P are both the 2nd letter in their respective triangles, angle X = angle P (A).

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You have also been asked to help set up the basketball court. What is the area of the circle? The radius is 1.8 (A = ?r2) m2 (gi

AleksandrR [38]

Answer:

The area of the circle is 10.18 m².

Step-by-step explanation:

We are given that,

Radius of the circle, r = 1.8 meters.

Since, we know,

Area of a circle = $\pi r^{2}$

So, we get,

Area of a circle = $\pi 1.8^{2}$

i.e. Area of a circle = $\pi 3.24$

i.e. Area of a circle = $10.18$

Hence, the area of the circle is 10.18 m².

4 0

3 years ago

Evaluate triple integral

kaheart [24]

Answer:

$\\ \frac{1}{8} e^{4a}-\frac{3}{4}e^{2a}+e^{a} -\frac{3}{8} \\\\or\\\\ \frac{e^{4a}-6e^{2a}+8e^{a}-3}{8}$

Step-by-step explanation:

$\\ \int\limits^{a}_{0} \int\limits^{x}_{0} \int\limits^{x+y}_{0} {e^{x+y+z}} \, dzdydx \\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} [\int\limits^{x+y}_{0} {e^{x+y}e^z} \, dz]dydx \\\\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} [e^{x+y}\int\limits^{x+y}_{0} {e^z} \, dz]dydx\\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} [e^{x+y}e^z\Big|_0^{x+y}]dydx \\\\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} [e^{x+y}e^{x+y}-e^{x+y}]dydx \\\\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} e^{2x+2y}-e^{x+y}dydx \\\\\\$

$\\=\int\limits^{a}_{0} [\int\limits^{x}_{0} e^{2x}e^{2y}-e^{x+y}dy]dx \\\\\\=\int\limits^{a}_{0} [\int\limits^{x}_{0} e^{2x}e^{2y}dy- \int\limits^{x}_{0}e^{x}e^{y}dy]dx \\\\\\u=2y\\du=2dy\\dy=\frac{1}{2}du\\\\\\=\int\limits^{a}_{0} [\frac{e^{2x}}{2}\int e^{u}du- e^x\int\limits^{x}_{0}e^{y}dy]dx \\\\\\=\int\limits^{a}_{0} [\frac{e^{2x}}{2}\cdot e^{2y}\Big|_0^x- e^xe^{y}\Big|_0^x]dx \\\\\\=\int\limits^{a}_{0} [\frac{e^{2x+2y}}{2} - e^{x+y}\Big|_0^x]dx \\\\$

$\\=\int\limits^{a}_{0} [\frac{e^{4x}}{2} - e^{2x}-\frac{e^{2x}}{2} + e^{x}]dx \\\\\\=\int\limits^{a}_{0} \frac{e^{4x}}{2} -\frac{3e^{2x}}{2} + e^{x}dx \\\\\\=\int\limits^{a}_{0} \frac{e^{4x}}{2}dx -\int\limits^{a}_{0}\frac{3e^{2x}}{2}dx + \int\limits^{a}_{0}e^{x}dx \\\\\\u_1=4x\\du_1=4dx\\dx=\frac{1}{4}du_1\\\\\u_2=2x\\du_2=2dx\\dx=\frac{1}{2}du_2\\\\\\=\frac{1}{8}\int e^{u_1}du_1 -\frac{3}{4}\int e^{u_2}du_2 + \int\limits^{a}_{0}e^{x}dx \\\\\\$

$\\=\frac{1}{8}e^{u_1}\Big| -\frac{3}{4}e^{u_2}\Big| + e^{x}\Big|_0^a \\\\\\=\frac{1}{8}e^{4x}\Big|_{0}^a -\frac{3}{4}e^{2x}\Big|_{0}^a + e^{x}\Big|_0^a \\\\\\=\frac{1}{8}e^{4x} -\frac{3}{4}e^{2x} + e^{x}\Big|_0^a \\\\\\=\frac{1}{8}e^{4a} -\frac{3}{4}e^{2a} + e^{a}-\frac{1}{8} +\frac{3}{4} -1\\\\\\=\frac{1}{8}e^{4a} -\frac{3}{4}e^{2a} + e^{a}-\frac{3}{8}\\\\\\$

Sorry if that took a while to finish. I am in AP Calculus BC and that was my first time evaluating a triple integral. You will see some integrals and evaluation signs with blank upper and lower boundaries. I just had my equation in terms of u and didn't want to get any variables confused. Hope this helps you. If you have any questions let me know. Have a nice night.

6 0

3 years ago

Determine whether the ratios 5:7 and 10:21 are equivalent

Alina [70]

Answer:

Step-by-step explanation:

No, thoose two ratios are not equivalent, but I can show you the ones that are equivalent, {You can write 5/7 or 10/14 or 20/28 or 40/56. There! 3 equivalent ratios.}

5 0

3 years ago

One of the two conditions for equilibrium states that the sum of the torques around every possible center of rotation must be eq

Alinara [238K]

Answer:

One of the two conditions for equilibrium states that the sum of the torques around every possible center of rotation must be equal to zero. Does this mean that when you analyze a body in equilibrium

Step-by-step explanation:

One of the two conditions for equilibrium states that the sum of the torques around every possible center of rotation must be equal to zero. Does this mean that when you analyze a body in equilibrium

5 0

3 years ago

Help me (question attached)

Verizon [17]

Answer:

a. ⅓ × 4

b. ⅖ × 3

c. ⅙ × 3

Step-by-step explanation:

i think

6 0

2 years ago