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raketka [301]
3 years ago
7

MARKING POEPLE AS BRIANLIST ALL DAY if you answer the question and it is right thank u

Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0

Answer: AAS that's what it should be

Step-by-step explanation:

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What is slop of the line that passes through the ponitss (5, -4) and (7, -4)
mylen [45]

Answer:

The slope is 0

Step-by-step explanation:

Points on the graph:

(5, -4) and (7, -4)

Slope:

m=(y2 - y1)/(x2 - x1)

m=(-4 + 4)/(7 - 5)

m= 0/2

m=0

6 0
3 years ago
T
chubhunter [2.5K]

9514 1404 393

Answer:

  $3277.23

Step-by-step explanation:

The future value of the CD with interest at rate r compounded semiannually for t years will be given by ...

  A = P(1 +r/2)^(2t)

where P is the principal value.

For the given rate and time, this is ...

  A = $2000(1 +0.05/2)^(2·10) = $2000(1.025^20) ≈ $3277.23

The value of the CD at maturity will be $3277.23.

6 0
3 years ago
what is an equation to represent for (Andre withdrew spending money from his checking account that initially had $982. What was
Paul [167]

Answer:

The Answer is w - 982 = 922 because it whatever money he took from the 982 lead to 922

Step-by-step explanation:

6 0
3 years ago
Jon makes a map of his neighborhood for a presentation. The scale of his map is 1inch:250 feet, How many feet do 6.5 inches repr
anygoal [31]
B 1625

250×6.5 equals B
3 0
3 years ago
A realtor uses a lock box to store the keys to a house that is for sale. The access code for the lock box consists of sixsix dig
vazorg [7]

Answer:

450,000 codes

Step-by-step explanation:

Number of digits in the access code = 6

Conditions:

  • First digit cannot be 2
  • Last digit must be odd

Since, there are 10 digits in total from 0 to 9 and first digit cannot be 2, there are 9 ways to fill the place of first digit.

Last digit must be odd. As there are 5 odd digits from 0 to 9, there are 5 ways to fill the last digit.

The central 4 digits can be filled by any of the 10 numbers. So, each of them can be filled in 10 ways.

According to the fundamental rule of counting, the total possible codes would be the product of all the possibilities of individual digits.

Therefore,

Number of possible codes = 9 x 10 x 10 x 10 x 10 x 5 = 450,000 codes

Hence, 450,000 different codes are possible for the lock box

8 0
4 years ago
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