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dimulka [17.4K]
3 years ago
9

You start at (2, -1). You move right 3 units and up 4 units. Where do you end?

Mathematics
2 answers:
vovangra [49]3 years ago
7 0

Answer:

(5,3)

Step-by-step explanation:

Lena [83]3 years ago
7 0

Answer:

(5, 3)

Step-by-step explanation:

(x, y)----> (x + 3, y + 4)

(2,  -1)----> (2 + 3, -1 + 4)

(5, 3)

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Usando la división de términos con la <u>misma base y diferentes exponentes</u>, se encuentra que la expresión simplificada está dada por:

k^{-5}l^{-8}n^6a^{-4} = \frac{n^6}{k^5l^8a^4}

<h3>¿Cómo dividir términos con la misma base y diferentes exponentes?</h3><h3 />

Para hacer la división, mantenemos la base y restamos los exponentes.

En este problema, la división es dada por:

\frac{-k^6l^1n^9}{-k^{11}l^9n^3a^4}

Por lo tanto, el resultado es:

k^{6-11}l^{1-9}n^{9-3}a^{0-4} = k^{-5}l^{-8}n^6a^{-4} = \frac{n^6}{k^5l^8a^4}

Como tanto el numerador como el denominador son negativos, la división es positiva.

Puede-se aprender más a cerca de la división de términos con la <u>misma base y diferentes exponentes</u> en brainly.com/question/15722035

#SPJ1

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