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Lunna [17]
3 years ago
8

What two gases easily diffuse through the phospholipid bilayer

Biology
1 answer:
natima [27]3 years ago
6 0

Answer:

Consider substances that can easily diffuse through the lipid bilayer of the cell membrane, such as the gases oxygen (O2) and CO2. O2 generally diffuses into cells because it is more concentrated outside of them, and CO2 typically diffuses out of cells because it is more concentrated inside of them.

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In some cells, a cell ____ is outside the plasma membrane
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Your answer is wall. A cell wall...
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What is the chromosome number produced in daughter cells as a result of mitosis?
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B. 2n.............................
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Green algae are more closely related to plants than they are to kelp.Why is this so?
In-s [12.5K]

Answer: Green Algae are closely related to plants.

Explanation: Green Algae are closely related to plants because of they possess photosynthetic pigments as plants.

Green algae and plants are closely related in that they can manufacture their own food from nutrients and sunlight through the process of photosynthesis

Green algae also possess the same carotenoids and chlorophyll a and b as land plants which make them closely related.

Kelps don't have these characteristics.

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3 years ago
How do the basic principles of inheritance, identified by Mendel in plants, differ from those in humans?
vlada-n [284]

Answer:

The Mendelian principles of inheritance ARE APPLIED IN HUMANS. Both plants and animalls posseses two alleles (forms) of each gene, and are inherited in Mendelian ways. Some genetic diseases are Mendelian diseases and are inherited according to Mendel laws, those are the diseases caused BY A SINGLE GENE. However, there are multigenic diseases (that involves more than one gene), multifactorial diseases (which involves several genes and environmental factors), and chromosomic diseases (like 21 trisomy) and all of these does not follow the Mendel laws.

Explanation:

4 0
3 years ago
A proton has a speed of 3.0 × 106 m/s in a direction perpendicular to a uniform magnetic field, and the proton moves in a circle
jeyben [28]

Answer:

The magnitude of the magnetic field is 0.156 T.

Explanation:

Given that,

Speed of a proton, v=3\times 10^6\ m/s

Radius of the circular path, r = 0.2 m

When the proton enters in the circular path, the centripetal force is balanced by the magnetic force such that :

\dfrac{mv^2}{r}=qvB\sin\theta

q is the charge on proton

Here, \theta=90^{\circ}

\dfrac{mv^2}{r}=qvB\\\\B=\dfrac{mv}{qr}\\\\B=\dfrac{1.67\times 10^{-27}\times 3\times 10^6}{1.6\times 10^{-19}\times 0.2}\\\\B=0.156\ T

So, the magnitude of the magnetic field is 0.156 T. Hence, this is the required solution.

3 0
3 years ago
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