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Vlada [557]
3 years ago
8

13.

Mathematics
1 answer:
dusya [7]3 years ago
4 0

Answer:

B - x=5

Step-by-step explanation:

If y=25 is 250% more than y=10, so multiply 2 by 250% and you get 5

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The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of inte
malfutka [58]

1. The area of the rhombus can be found by the formula

A=\dfrac{d_1\cdot d_2}{2}, where d_1,\ d_2 are rhombus's diagonals.

Note that d_1=4.5\ dm=45\ cm, then

540=\dfrac{45\cdot d_2}{2},\\ \\540\cdot 2=45d_2,\\ \\d_2=24\ cm.

2. The diagonals of rhombus are perpendicular and are bisectors of each other. Then the triangle formed with halfs of diagonals is right triangles with legs

\dfrac{d_1}{2}=22.5\ cm,\ \dfrac{d_2}{2}=12\ cm.

The hypotenuse of this triangle is the rhombus's side. By the Pythagorean theorem

\text{rhombus's side}^2=(22.5)^2+12^2=506.25+144=650.25,\\ \\\text{rhombus's side}=25.5\ cm.

3. The distance between the point of intersection of the diagonals and the side of the rhombus is the height of right triangle considered above.

Use twice the Pythagorean theorem to find this height:

\left\{\begin{array}{l}x^2+h^2=12^2\\(25.5-x)^2+h^2=22.5^2,\end{array}\right.

where x is projection of leg 12 cm and h is height.

Subtract the first equation from the second:

(25.5-x)^2+h^2-x^2-h^2=22.5^2-12^2,\\ \\650.25-51x=506.25-144,\\ \\51x=650.25-362.25=288,\\ \\x=\dfrac{96}{17}\ cm.

Then

h^2=144-\left(\dfrac{96}{17}\right)^2=144-\dfrac{9216}{289}=\dfrac{32400}{289},\\ \\h=\dfrac{180}{17}\ cm.

Answer: h=\dfrac{180}{17}\ cm.

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3 years ago
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Review the table of values for function h(x).
muminat

Answer:

a) The limit does not exist because the values of h(x) seem to oscillate between random values around x = 9.

Step-by-step explanation:

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3 years ago
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Use the graph to fill in the blank with the correct number.
defon

Answer:

3029

Step-by-step explanation:

5 0
1 year ago
Please help me ASAP
elena-14-01-66 [18.8K]

Answer:

∠ 1 = 123°

Step-by-step explanation:

One way

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ 1 is an external angle of the triangle, thus

∠ 1 = 90° + 33° = 123°

Second way

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 given angles from 180 for third angle in Δ

third angle = 180° - (90 + 33)° = 180° - 123° = 57°

The third angle and ∠ 1 form a straight angle and are supplementary, thus

∠ 1 = 180° - 57° = 123°

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Unsimplified ratio of circles to triangles:
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Step-by-step explanation:

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