The equation of the vertical line that satisfies the condition is x=0.
Answer:
In the form of
Y= mx+c
Y= 1/2x +2
m = 1/2
Step-by-step explanation:
A linear equation in it's standard form is in the format
Y= mx+c
Where m is the slope and c is the y intercept
Let's use these two points to determine both the slope and the equation
(2, 3), (4,4)
Slope= (y2-y1)/(x2-x1)
Slope= (4-3)/(4-2)
Slope= 1/2
Equation of the linear function
(Y-y1)/(x-x1)= m
(Y-3)/(x-2)= 1/2
2(y-3) = x-2
2y -6 = x-2
2y= x-2+6
2y= x+4
Y= 1/2x +2
Given:
Point is T(-3,8).
To find:
The coordinates of T' after 
.
Solution:
We know that, means the figure reflected across the x-axis then reflected across y-axis.
If a figure reflected across x-axis, then
If a figure reflected across y-axis, then
Therefore, the required point is T'(3,-8).
Answer:
5x+3>4x+7
-4x -4x
x+3>7
-3 -3
x>4
so the answer will be the second
Step-by-step explanation:
