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3 years ago

Convert 4/7 to 42nds

Mathematics

1 answer:

Mademuasel [1]3 years ago

7 0

Answer:

24... I hoped dis helped.

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Which of the following starts with a contradiction of what you are trying to prove?

Juliette [100K]

C is the answer

Hope this helps!

4 0

3 years ago

Write an equation for the line in slope-intercept form

quester [9]

Answer:

y = -3/1x + 2

Step-by-step explanation:

1. Find the slope

The points I will use are (-1,5) and (0,2), where x1 = -1, y1 = 5, x2 =0, and y2 =2.

y2-y1/x2-x1

2-5/0-(-1) = -3/1

2. Find the y-intercepy

y = mx + b

You can use any x or y point. I'll use (-1,5)

m= slope, which is -3/1

5= -3/1(-1) +b

5= 3 + b

Subtract 3 from 5 and 3 to get 2=b.

3. Rewrite in slope-intercept form

y = -3/1x + 2

4 0

3 years ago

What is an equation of a line which passes through (6,9) and is perpendicular to the line whose equation is 4x − 6y = 15?

Svetllana [295]

Given:

The equation of the line passes through the point (6,9) and is perpendicular to the line whose equation is $4 x-6 y=15$

We need to determine the equation of the line.

Slope:

Let us convert the equation to slope - intercept form.

$-6 y=15-4x$

$y=\frac{2}{3}x-\frac{5}{2}$

From the above equation, the slope is $m_1=\frac{2}{3}$

Since, the lines are perpendicular, the slope of the line can be determined using the formula,

$m_1 \cdot m_2=-1$

$\frac{2}{3} \cdot m_2=-1$

$m_2=-\frac{3}{2}$

Therefore, the slope of the equation is $m=-\frac{3}{2}$

Equation of the line:

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the point (6,9) and the slope $m=-\frac{3}{2}$ in the above formula, we get;

$y-9=-\frac{3}{2}(x-6)$

Simplifying the terms, we get;

$2(y-9)=-3(x-6)$

$2y-18=-3x+18$

$3x+2y=36$

Thus, the equation of the line is $3x+2y=36$

3 0

3 years ago

If this is equal to 8 find x

dolphi86 [110]

I think it is A. not sure though

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%28%20%5Cfrac%7B1%7D%7B2%7D%20%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%20%5Cfrac%7B1%7D%7B2%7D%20ab

Zigmanuir [339]

Answer:

$\frac{1}{2}$ (a + 2b)(a - b)

Step-by-step explanation:

Assuming you require the expression to be factored

Given

$\frac{1}{2}$ a² + $\frac{1}{2}$ ab - b² ← factor out $\frac{1}{2}$ from each term

= $\frac{1}{2}$ (a² + ab - 2b²) ← factor the quadratic

Consider the factors of the coefficient of the b² term(- 2) which sum to give the coefficient of the ab- term (+ 1)

The factors are + 2 and - 1, since

2 × - 1 = - 2 and 2 - 1 = + 1, thus

a² + ab - 2b² = (a + 2b)(a - b) and

$\frac{1}{2}$ a² + $\frac{1}{2}$ ab - b² = $\frac{1}{2}$ (a + 2b)(a - b)

5 0

3 years ago