If A and B are independent, then
.
a.



b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:



c. DeMorgan's law can be used here too:



That answer is x≤−8
Inequality:
8x−8≤−72
Step number 1: You have to Add 8 to both sides.
8x−8+8≤−72+8
8x≤−64
Step number 2: You have to Divide both sides by 8.
8x
/8 ≤ −64
/ 8
Ur Answer:
x≤−8
Hope this helps :)
Sorry but I can't understand your language







The first case occurs in

for

and

. Extending the domain to account for all real

, we have this happening for

and

, where

.
The second case occurs in

when

, and extending to all reals we have

for

, i.e. any even multiple of

.
To find the <span>percentaje</span> we need to <span>divided</span> the <span>tataol</span> by the amount we end up having.
22.50/19.50=1.15
<span>then</span> we multiply by 100
115%
Then to find the <span>percentaje</span> increase we subtract
115%-100= 15%
So it has an <span>increament</span> of 15%