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Elodia [21]
3 years ago
5

Select the correct choices that complete the sentence below. The​ ______ class limit is the smallest value within the class and

the​ ______ class limit is the largest value within the class.a. Minimumb. Lowerc. Maximumd. Upper
Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0

Answer: Hello!

Lets segment our phrase:

The​ ______ class limit is the smallest value within the class.

The lower limit of a sequence, is a therm that is smaller than al the therms in the sequence, and does not belong in the sequence, for other part, the minumum refers to the smaller therm in the sequence, here you can see that the phrase is refering to "the smallest value within the class" so this number is in the set, then the correct answer is "minumum".

and the​ ______ class limit is the largest value within the class.

Here again, we are talking of values within the set (where the set is the class in this problem) then the correct answer in this case is "maximum".

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15. The height and yolume of a cylinder are 4cm and 616cm respectively. Calculate the diameter of the base. (take t = 27 쪽 A. 7c
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Step-by-step explanation:

Given that,

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  • Volume of cylinder = 616 cm³

To find,

  • Diameter of the base = ?

Firstly we'll find the base radius of the cylinder.

\longmapsto\rm{V_{(Cylinder)} = \pi r^2h}\\

<u>Accordi</u><u>ng</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>qu</u><u>estion</u><u>,</u>

\longmapsto\rm{616= \dfrac{22}{7} \times r^2 \times 4}\\

\longmapsto\rm{616 \times 7 = 22 \times r^2 \times 4}\\

\longmapsto\rm{4312 = 88 \times r^2 }\\

\longmapsto\rm{\cancel{\dfrac{4312}{88}} =  r^2 }\\

\longmapsto\rm{49 =  r^2 }\\

\longmapsto\rm{\sqrt{49} =  r }\\

\longmapsto\rm{7 \; cm =  r }\\

Now,

\longmapsto\rm{Diameter = 2r }\\

\longmapsto\rm{Diameter = 2(7 \; cm) }\\

\longmapsto\bf{Diameter = 14 \; cm}\\

The required answer is 14 cm.

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V=1/3nr^2h ; solve for r
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Step-by-step explanation:

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