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2 years ago

How am i Invisible???????????????/

Mathematics

2 answers:

deff fn [24]2 years ago

3 0

Answer:

being blind

Step-by-step explanation:

if you are blind you can not see your self so there for you are invisable

avanturin [10]2 years ago

3 0

Answer:

Have you tried to put a profile picture that's bold and bright? and not white and blank? maybe it's because its a brainly techno error

Step-by-step explanation:

You might be interested in

Sum of 2/3 + (-1/3) i cant find the answer

arsen [322]

Answer:

1/3

Step-by-step explanation:

2/3 plus -1/3 is the same as subtracting 1/3 from 2/3.

6 0

3 years ago

Read 2 more answers

Write the formula that expresses the relationship described "c varies directly<br> as a"

olga55 [171]

Answer:

a+b+c

find b

then

add a+b+c

7 0

3 years ago

Which equation represents a parabola that has a focus of (0 0) and a directrix of y = 2

mel-nik [20]

ANSWER

$x ^{2} = - 4(y - 1).$

EXPLANATION

Since the parabola has the (0, 0) and the directrix at y=2.

The equation is of the form

${(x - h)}^{2} = - 4p(y - k)$

where (h,k) is the vertex.

The vertex is half way between the directrix and the focus.

The vertex will be at (0,1)

and is the distance from the vertex to the focus which is 1.

${(x - 0)}^{2} = - 4(1)(y - 1)$

$x ^{2} = - 4(y - 1)$

7 0

3 years ago

Find the average rate of change of the function over the given interval

sattari [20]

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\$

$\bf h(t)=cot(t)\implies h(t)=\cfrac{cos(t)}{sin(t)}\quad 
\begin{cases}
t_1=\frac{\pi }{4}\\
t_2=\frac{3\pi }{4}
\end{cases}\implies \cfrac{h\left( \frac{3\pi }{4} \right)-h\left( \frac{\pi }{4} \right)}{\frac{3\pi }{4}-\frac{\pi }{4}}
\\\\\\$

$\bf \cfrac{\frac{cos\left( \frac{3\pi }{4} \right)}{sin\left( \frac{3\pi }{4} \right)}-\frac{cos\left( \frac{\pi }{4} \right)}{sin\left( \frac{\pi }{4} \right)}}{\frac{\pi }{2}}\implies \cfrac{-1-1}{\frac{\pi }{2}}\implies \cfrac{-2}{\frac{\pi }{2}}\implies -\cfrac{4}{\pi }\\\\\\
-------------------------------\\\\$

$\bf h(t)=cot(t)\implies h(t)=\cfrac{cos(t)}{sin(t)}\quad 
\begin{cases}
t_1=\frac{\pi }{3}\\
t_2=\frac{3\pi }{2}
\end{cases}\implies \cfrac{h\left( \frac{3\pi }{2} \right)-h\left( \frac{\pi }{3} \right)}{\frac{3\pi }{2}-\frac{\pi }{3}}
\\\\\\$

$\bf \cfrac{\frac{cos\left( \frac{3\pi }{2} \right)}{sin\left( \frac{3\pi }{2} \right)}-\frac{cos\left( \frac{\pi }{3} \right)}{sin\left( \frac{\pi }{3} \right)}}{\frac{9\pi -2\pi }{6}}\implies \cfrac{\frac{0}{-1}-\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}}{\frac{7\pi }{6}}\implies\cfrac{-\frac{1}{\sqrt{3}}}{\frac{7\pi }{6}}\implies -\cfrac{\sqrt{3}}{3}\cdot \cfrac{6}{7\pi }
\\\\\\
-\cfrac{2\sqrt{3}}{7\pi }$

8 0

3 years ago

What is x?

iren2701 [21]

X = 5 -

-7x - 3x + 2 = -8x - 8
+ 7x +7x
-3x + 2 = -x - 8
+3x +3x
2 = 2x -8
+8 +8
10 = 2x
/2 /2
x = 5

7 0

3 years ago

Read 2 more answers