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3 years ago

2= d-11/3 100 points if u answer pls help asap

Mathematics

2 answers:

hjlf3 years ago

8 0

Answer:

i hope this works

Step-by-step explanation:

d=17/3

d=5.666

d=5 2/3

ch4aika [34]3 years ago

8 0

Answer:

Solution given:

2=d- $\frac{11}{3}$

2+ $\frac{11}{3}$ =d

d= $\frac{6+11}{3}$

d= $\frac{17}{3}$ or $5\frac{2}{3}$

is your answer

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Answer soon please! Question and answers are in the photograph attached.

-BARSIC- [3]

Answer:

Δ MLP ~ Δ HKG

By S-A-S similarity Postulate.

Step-by-step explanation:

Given:

In Δ MLP

MP = 20 ,

LP = 15

∠ P = 42°

In Δ HKG

HG = 16 ,

KG = 12

∠G = 42°

To Prove:

Δ MLP ~Δ HKG

Proof:

In Δ MLP and Δ HKG

$\dfrac{MP}{HG}= \dfrac{20}{16}=\dfrac{5}{4}$ ..........( 1 )

$\dfrac{LP}{KG}= \dfrac{15}{12}=\dfrac{5}{4}$ ..............( 2 )

∴ $\dfrac{MP}{HG}=\dfrac{LP}{KG}$ ...From 1 and 2

∠P ≅ ∠ G = 42° ...............Given

∴ Δ MLP ~Δ HKG ......{ By S-A-S similarity test}............Proved

4 0

3 years ago

Graph the function y = -2x + 1 using inputs of -1,0, 1, and 2.

Vladimir [108]

Answer: (-1,3)

(0,1)

(1,-1)

(2,-3)

Step-by-step explanation: For example, you put -1 as x in the equation, and then solve, your answer would be the y, and the number you inputted would be the x.

3 0

4 years ago

Astrid is in charge of building a new fleet of ships. Each ship requires 40 tons of wood, and accommodates 300 sailors. She rece

gogolik [260]

Answer:Astrid needs 280 tons of wood

Step-by-step explanation:

Because:

1 ship requires 40 tons of wood=accomodates 300 sailors

We must:

2100, sailors needed to be accomodated

300, sailors that can be accomodated by 1 ship that requires 40 tons of wood

=7 groups of 300 sailors that can be accomodated by 1 ship that requires 40 tons of wood.

So:

I ship that requires 40 tons of wood × the 7, groups = 280 tons of wood.

I hope this helps! Im sorry its too complicated.

Simplier:

2100 ÷ 300= 7

40 × 7= 280

6 0

4 years ago

Line A is represented by the following equation: x + y = 2

jeka57 [31]

A system of linear equations will have no solution when the two lines making up the equation are parallel. Here, a system having x + y = 2 will have no solution if the second equation is x + y = a. where a is any real number.

5 0

4 years ago

Simplify the following 3/5×(7/10+2/5)/ 5 2/3+1 3/8-2 1/4

Inessa [10]

Answer:

(-2579)/3400

Step-by-step explanation:

Simplify the following:

3/5 (7/10 + 2/5)/(5 + 2/3) + 1 + 3/8 - (2 + 1/4)

(3 (7/10 + 2/5)/(5 + 2/3))/5 = (3 (7/10 + 2/5))/(5 (5 + 2/3)):

(3 (7/10 + 2/5))/(5 (2/3 + 5)) + 1 + 3/8 - (2 + 1/4)

Put 5 + 2/3 over the common denominator 3. 5 + 2/3 = (3×5)/3 + 2/3:

(3 (7/10 + 2/5))/(5 (3×5)/3 + 2/3) + 1 + 3/8 - (2 + 1/4)

3×5 = 15:

(3 (7/10 + 2/5))/(5 (15/3 + 2/3)) + 1 + 3/8 - (2 + 1/4)

15/3 + 2/3 = (15 + 2)/3:

(3 (7/10 + 2/5))/(5 (15 + 2)/3) + 1 + 3/8 - (2 + 1/4)

15 + 2 = 17:

(3 (7/10 + 2/5))/(5×17/3) + 1 + 3/8 - (2 + 1/4)

Put 7/10 + 2/5 over the common denominator 10. 7/10 + 2/5 = 7/10 + (2×2)/10:

(3 7/10 + (2×2)/10)/((5×17)/3) + 1 + 3/8 - (2 + 1/4)

2×2 = 4:

(3 (7/10 + 4/10))/((5×17)/3) + 1 + 3/8 - (2 + 1/4)

7/10 + 4/10 = (7 + 4)/10:

(3 (7 + 4)/10)/((5×17)/3) + 1 + 3/8 - (2 + 1/4)

7 + 4 = 11:

(3×11/10)/(5×17/3) + 1 + 3/8 - (2 + 1/4)

5×17/3 = (5×17)/3:

(3×11/10)/((5×17)/3) + 1 + 3/8 - (2 + 1/4)

3×11/10 = (3×11)/10:

((3×11)/10)/((5×17)/3) + 1 + 3/8 - (2 + 1/4)

Multiply the numerator by the reciprocal of the denominator, ((3×11)/10)/((5×17)/3) = (3×11)/10×3/(5×17):

(3×11×3)/(5×17×10) + 1 + 3/8 - (2 + 1/4)

5×17 = 85:

(3×11×3)/(85×10) + 1 + 3/8 - (2 + 1/4)

85×10 = 850:

(3×11×3)/850 + 1 + 3/8 - (2 + 1/4)

3×11 = 33:

(33×3)/850 + 1 + 3/8 - (2 + 1/4)

33×3 = 99:

99/850 + 1 + 3/8 - (2 + 1/4)

Put 2 + 1/4 over the common denominator 4. 2 + 1/4 = (4×2)/4 + 1/4:

99/850 + 1 + 3/8 - (4×2)/4 + 1/4

4×2 = 8:

99/850 + 1 + 3/8 - (8/4 + 1/4)

8/4 + 1/4 = (8 + 1)/4:

99/850 + 1 + 3/8 - (8 + 1)/4

8 + 1 = 9:

99/850 + 1 + 3/8 - 9/4

Put 99/850 + 1 + 3/8 - 9/4 over the common denominator 3400. 99/850 + 1 + 3/8 - 9/4 = (4×99)/3400 + 3400/3400 + (425×3)/3400 + (850 (-9))/3400:

(4×99)/3400 + 3400/3400 + (425×3)/3400 + (850 (-9))/3400

4×99 = 396:

396/3400 + 3400/3400 + (425×3)/3400 + (850 (-9))/3400

425×3 = 1275:

396/3400 + 3400/3400 + 1275/3400 + (850 (-9))/3400

850 (-9) = -7650:

396/3400 + 3400/3400 + 1275/3400 + (-7650)/3400

396/3400 + 3400/3400 + 1275/3400 - 7650/3400 = (396 + 3400 + 1275 - 7650)/3400:

(396 + 3400 + 1275 - 7650)/3400

| 1 | 1 | 1 |

| 3 | 4 | 0 | 0

| 1 | 2 | 7 | 5

+ | | 3 | 9 | 6

| 5 | 0 | 7 | 1:

(5071 - 7650)/3400

5071 - 7650 = -(7650 - 5071):

(-(7650 - 5071))/3400

| | | 14 |

| | 5 | 4 | 10

| 7 | 6 | 5 | 0

- | 5 | 0 | 7 | 1

| 2 | 5 | 7 | 9:

Answer: (-2579)/3400

4 0

4 years ago