2 years ago

To solve the equation -10x = 100 by balancing, you should:

Mathematics

1 answer:

MArishka [77]2 years ago

8 0

Eradication team hid behind habit

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Irina18 [472]

Answer:

$\frac{x+7}{3}$ (the second option)

Step-by-step explanation:

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2 years ago

PLS HELP<br> Solve the equation for m. Show your work.<br> 19+m=30

Lena [83]

Answer:

Step-by-step explanation:

19 + m = 30

m = 30 - 19

m = 11

Hope it helps

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2 years ago

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Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

2 years ago

Simply <br>x + 50 × 10 = 150

Doss [256]

Answer:

x + 50 × 10 = 150

x+500=150

x=150-500=-350

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2 years ago

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miss Avery is going to bring the select one student from your class to read a poem out loud. There are 15 boys and 13 girls in t

tester [92]

There are 15 boys what are you asking the sentence is not complete

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2 years ago

To solve the equation -10x = 100 by balancing, you should:​

To solve the equation -10x = 100 by balancing, you should: