Question

A line passes through (2, -6) and (-1,6), what is its equation?

Answer 1

Answer:

let x1=2, y1 = -6 ,x2 = -1, y2 = 6

first we find gradient of the line

gradient = (y2-y1) / (x2 -x1)

(6-(-6))/(-1-2)

(6+6)/(-3)

12/-3

-4

equation is;

M=( y-y1)/(x-x1)

whereM is a gradient

we substitute

-4=(y-(-6))/(x-2(

-4=(y+6)/(x-2)

by cross multiplication

-4(x-2)=(y+6)

-4x+8=y+6

-4x+8-6-y=0

-4x-y+2=0