It would be a 50/50 chance that all of them would be girls
Answer:
The expected revenue of an airline ticket sold by this travel website is $408
Step-by-step explanation:
For the revenues per ticket we have;
airline A; 600
airline B; 360
For the probability of choosing the airlines we have;
airline A; 20% = 0.2
airline B; 80% = 0.8
Therefore, the expected revenue of an airline ticket sold by this travel website is;
600(0.2) + 360(0.8) = 408
Therefore, the expected revenue of an airline ticket sold by this travel website is $408
Let's assume
the number of bags of candy =x
the number of bags of cookies =y
There were 5 more bags of cookies sold than candy
so, we get
![y=x+5](https://tex.z-dn.net/?f=y%3Dx%2B5)
Bags of candy cost $5.50
so, total cost of candy is
![=5.50x](https://tex.z-dn.net/?f=%3D5.50x)
bags of cookies cost $3.50
so, total cost of cookies is
![=3.50y](https://tex.z-dn.net/?f=%3D3.50y)
so,
total cost = (total cost of candy)+(total cost of cookies)
we get
total cost =5.50x+3.50y
so, we can plug
![5.50x+3.50y=53.50](https://tex.z-dn.net/?f=5.50x%2B3.50y%3D53.50)
now, we can plug y
![5.50x+3.50(x+5)=53.50](https://tex.z-dn.net/?f=5.50x%2B3.50%28x%2B5%29%3D53.50)
![5.5x\cdot \:10+3.5\left(x+5\right)\cdot \:10=53.5\cdot \:10](https://tex.z-dn.net/?f=5.5x%5Ccdot%20%5C%3A10%2B3.5%5Cleft%28x%2B5%5Cright%29%5Ccdot%20%5C%3A10%3D53.5%5Ccdot%20%5C%3A10)
![55x+35\left(x+5\right)=535](https://tex.z-dn.net/?f=55x%2B35%5Cleft%28x%2B5%5Cright%29%3D535)
![55x+35x+175=535](https://tex.z-dn.net/?f=55x%2B35x%2B175%3D535)
![90x+175=535](https://tex.z-dn.net/?f=90x%2B175%3D535)
![90x+175-175=535-175](https://tex.z-dn.net/?f=90x%2B175-175%3D535-175)
![90x=360](https://tex.z-dn.net/?f=90x%3D360)
![x=4](https://tex.z-dn.net/?f=x%3D4)
now, we can find y
![y=x+5](https://tex.z-dn.net/?f=y%3Dx%2B5)
![y=4+5](https://tex.z-dn.net/?f=y%3D4%2B5)
![y=9](https://tex.z-dn.net/?f=y%3D9)
so,
the number of bags of candy =4
the number of bags of cookies =9............Answer
Answer:
0.6988
Step-by-step explanation:
Given that the number of people who use the ATM at night outside your local bank branch can be modeled as a Poisson distribution.
Let X be the number of customers arriving between 10 and 11 am.
X is Poisson with mean= 1.2
Required probability
= the probability that in the hour between 10 and 11 PM at least one customer arrives
= P(X≥1)
=1-P(X=0)
=1-0.3012
= 0.6988
Step-by-step explanation:
(a-b)^2=a^2-2ab+b^2
X^2-2(X)(5)+5^2
Ans C
X^2-10X+25