You have two equations.
since the second is already isolated, sub in x-4 for every y in equation 1 so that
$x^{2} - 4 [(x-4)^{2}] =16
$
expand, collect like terms, factor to find x, then plug x value back into original equation to find y

3 0

3 years ago

Read 2 more answers

Solve the system using elimination and describe your steps. Be sure to verify your solution. • x = y - 3 2x + y = 12

hram777 [196]

So these are our two equations: $2x+y=12\\x=y-3$

Before we can use elimination, subtract y on both sides of the first equation: $2x=-y+12\\x=y-3$

Now we are able to use elimination. To eliminate the y variable, add the two equations together to get $3x=9$ . From here we can solve for x.

For this, just divide both sides by 3 and your first answer will be $x=3$

Now that we have the value of x, substitute it into either equation to solve for y:

$2*3+y=12\\6+y=12\\y=6\\\\3=y-3\\6=y$

<u>In short, x = 3 and y = 6.</u>

6 0

4 years ago

What is the sum of 8x^2-x+4 and x-5 is

shtirl [24]

Answer:

8x^2-1

Step-by-step explanation:

8x^2-x+4+x-5=8x^2-x+x+4-5=8x^2+4-5=8x^2-1

3 0

3 years ago