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liraira [26]
3 years ago
14

If im downloading a game at 4mb/s how many minutes would it take to download 25 GB

Computers and Technology
2 answers:
xxMikexx [17]3 years ago
7 0

Answer:

File size  

25  GB  

Connection type Download speed Download time

Modem    28,8 kbit/s                   2071:15:40

Modem     56,6 kbit/s                         1065:13:12

ADSL       256 kbit/s                         233:01:00

ADSL       512 kbit/s                         116:30:30

ADSL       1 Mbit/s                                     59:39:08

ADSL             2 Mbit/s                                     29:49:34

ADSL             8 Mbit/s                                     07:27:23

ADSL             24 Mbit/s                                     02:29:07

LAN             10 Mbit/s                                                 05:57:54

LAN             100 Mbit/s                                     00:35:47

Turbo 3G 7,2 Mbit                           08:17:06

4G             80 Mbit/s                                     00:44:44

Hopefully this helps somewhat

AlexFokin [52]3 years ago
3 0

Answer:

104 minutes.

Explanation:

25gb = 25,000mbs

Rate: 4mb/s

Divide 25,000mb/4mbs, results in 6,250sec. 6,250/60 = 104.16, so it would end up being around 104 minutes.

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Goshia [24]

Answer:A) Internet cafe

Explanation: Internet cafe is the place that provides the internet service to the public and helps them to access the internet .These cafes can be used by the public who are travelers, people who don't have access at home etc.This internet cafe works on the basis of the hourly rate that it takes from the public.

Rest of the options are incorrect  as intranet and extranet are types of network and LogMeIn is a desktop service .thus, the correct option is option(A).

8 0
3 years ago
Given two ArrayLists of sorted strings (alphabetically ascending), write down a method to merge these sorted strings’ ArrayLists
Elena-2011 [213]

Answer:

see explaination

Explanation:

import java.util.ArrayList;

import java.util.Arrays;

public class Merge {

public static ArrayList<String> mergeList(ArrayList<String> lst1, ArrayList<String> lst2) {

ArrayList<String> result = new ArrayList<String>();

int i = 0, j = 0;

while (i < lst1.size() || j < lst2.size()) {

if (i < lst1.size() && (j >= lst2.size() || lst1.get(i).compareTo(lst2.get(j)) < 0)) {

result.add(lst1.get(i++));

} else {

result.add(lst2.get(j++));

}

}

return result;

}

public static void main(String[] args) {

ArrayList<String> lst1 = new ArrayList<>(Arrays.asList("Austin", "Dallas", "San Fransisco"));

ArrayList<String> lst2 = new ArrayList<>(Arrays.asList("Boston", "Chicago", "Denver", "Seattle"));

System.out.println(mergeList(lst1, lst2));

}

}

8 0
3 years ago
In a linked chain implementation of a queue, the performance of the enqueue operation
alexdok [17]

Answer:

A.O(1)

Explanation:

In the implementation of queue by using linked chain the performance of  the enqueue operation is O(1).We have to  maintain  two pointers one  head and the other tailand  for  enqueue operation  we have to insert element  to the next of the tail and then  make that element  tail.Which takes O(1) time.

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3 years ago
Can you prove that the bleu areas are the same please?
Nookie1986 [14]

\huge\color{darkred}{ \tt{NO!!}}

8 0
2 years ago
Read 2 more answers
Look at the following partial class definition, and then respond to the questions that follow it:
zhannawk [14.2K]

Solution :

a.

public Book($\text{String title}$, String author, $\text{String publisher}$, int $\text{copiesSold}$) {

 this.$\text{title}$ = $\text{title}$;

 this.$\text{author}$ = $\text{author}$;

 this.$\text{publisher}$ = $\text{publisher}$;

 this.$\text{copiesSold}$ = $\text{copiesSold}$;

b). $\text{public String}$ getTitle() {

 return $\text{title}$;

}

$\text{public void}$ setTitle($\text{String title}$) {

 this.$\text{title}$ = $\text{title}$;

}

$\text{public String}$ getAuthor() {

 return author;

}

$\text{public void}$ setAuthor(String author) {

 this.$\text{author}$ = $\text{author}$;

}

$\text{public String}$ getPublisher() {

 return $\text{publisher}$;

}

$\text{public void}$ setPublisher(String $\text{publisher}$) {

 this.$\text{publisher}$ =$\text{publisher}$;

}

public int get$\text{copiesSold}$() {

 return $\text{copiesSold}$;

}

$\text{public void}$ set$\text{copiesSold}$(int $\text{copiesSold}$) {

 this.$\text{copiesSold}$ = $\text{copiesSold}$;

}

4 0
3 years ago
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