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Naddika [18.5K]
3 years ago
15

4) Which is a more efficient way to determine the optimal number of multiplications in a matrix-chain multiplication problem: en

umerating all the ways of parenthesizing the product and computing the number of multiplications for each, or running RECURSIVE-MATRIX-CHAIN? Justify your answer

Computers and Technology
1 answer:
Assoli18 [71]3 years ago
3 0

Answer:

Running RECURSIVE-MATRIX-CHAIN is asymptotically more efficient than enumerating all the ways of parenthesizing the product and computing the number of multiplications of each.

the running time complexity of enumerating all the ways of parenthesizing the product is n*P(n) while in case of RECURSIVE-MATRIX-CHAIN, all the internal nodes are run on all the internal nodes of the tree and it will also create overhead.

Explanation:

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Answer:

Explanation:

A computer virus is a form of malicious software that piggybacks onto legitimate application code in order to spread and reproduce itself.

Like other types of malware, a virus is deployed by attackers to damage or take control of a computer. Its name comes from the method by which it infects its targets. A biological virus like HIV or the flu cannot reproduce on its own; it needs to hijack a cell to do that work for it, wreaking havoc on the infected organism in the process. Similarly, a computer virus isn't itself a standalone program. It's a code snippet that inserts itself into some other application. When that application runs, it executes the virus code, with results that range from the irritating to the disastrous.

Computer virus symptoms

How can you tell if a virus has slipped past your defenses? With some exceptions, like ransomware, viruses are not keen to alert you that they've compromised your computer. Just as a biological virus wants to keep its host alive so it can continue to use it as a vehicle to reproduce and spread, so too does a computer virus attempt to do its damage in the background while your computer still limps along. But there are ways to tell that you've been infected. Norton has a good list; symptoms include:

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7 0
3 years ago
Write a q basic program to find the sum of all the even numbers from 1 to 50​
Artist 52 [7]

Answer:

CLS

M=2

SUM=0

DO WHILE M<=50

SUM=SUM+M

M=M+2

LOOP

PRINT " The sum of all even numbers between 1 and 50 is"; sum

5 0
3 years ago
Please debug the below code in Java please.
lisabon 2012 [21]

Answer:

Check the explanation

Explanation:

//Bugs are highlighted in bold text

class Invoice

Declarations

private num invoiceNumber

private string customer

private num balanceDue

private num tax

public void setInvoiceNUMBER(num number)

Declarations

num LOW_NUM = 1000

num HIGH_NUM = 9999

if number > HIGH_NUM then

invoiceNumber = 0

else

if number < LOW_NUM then

invoiceNumber = 0

else

invoiceNumber = num

endif

return

public void setCustomer(string cust)

customer = cust

return

public void setBalanceDue(num balance)

//Bug balanceDue is Invoice class varible

//but it is assigned to balance .it gives error

balance = balanceDue

setTax()

return

private void setTax()

Declarations

//Bug TAX_RATE is declared as string

//but assigned a double value

string TAX_RATE = 0.07

tax = tax * TAX_RATE

return

public void displayInvoice()

output "Invoice #", invoiceNumber

output "Customer: ", customer

output "Due: ", balanceDue

output "Tax: ", taxDue

//Bug

//Invoice class has no variable called balance .it should be balanceDue

output "Total ", balance + taxDue

return

endClass

start

Declarations

Invoice inv1

Invoice inv2

Invoice inv3

//Warning

//it gives warning object taken but not initilaized

Invoice inv4

inv1.setInvoiceNumber(1244)

inv1.setCustomer("Brown")

inv1.setBalanceDue(1000.00)

inv1.displayInvoice()

inv2.setInvoiceNumber(77777)

inv2.setCustomer("Jenkins")

inv2.setBalanceDue(2000.00)

inv2.displayInvoice()

inv3.setInvoiceNumber(888)

inv3.setCustomer("Russell")

inv3.setBalanceDue(3000.00)

//Bug

//setTax method of Invioce doesnot take any arguments

inv3.setTax(210.00)

inv3.displayInvoice()

stop

//Here is the complete program in c++

//Run the program using Microsoft visual studio 2010 vc++

#include<iostream>

#include<iomanip>

#include<string>

using namespace std;

class Invoice

{

//class varibales

private:

           int invoiceNumber;

           string customer;

           double balanceDue;

           double tax;

//class methods

public:

           void setCustomer(string cus);

           void displayInvoice();

           void setBalanceDue(double balance);

           void setInvoiceNUMBER(int number);

           void setTax();

};

void Invoice::displayInvoice()

{

cout<< setw(10)<<"Invoice #"<<setw(5)<<invoiceNumber<<endl;

cout<<setw(10)<<"Customer: "<<setw(5)<<customer<<endl;

cout<<setw(10)<<"Due: "<<setw(5)<<balanceDue<<endl;

cout<<setw(10)<<"Tax: "<<setw(5)<<tax<<endl;

//Bug

//Invoice class has no variable called balance .it should be balanceDue

cout<< "Total "<< balanceDue + tax<<endl;

}

void Invoice::setCustomer(string cust)

{

customer = cust;

}

void Invoice::setInvoiceNUMBER(int number)

{

const int LOW_NUM = 1000;

const int HIGH_NUM = 9999;

if( number > HIGH_NUM )

invoiceNumber = 0;

else

if (number < LOW_NUM )

       invoiceNumber = 0;

else

   invoiceNumber = number;

}

void Invoice::setBalanceDue(double balance)

{

balanceDue = balance;

}

void Invoice::setTax()

{

double TAX_RATE = 0.07;

tax = balanceDue * TAX_RATE;

}

int main()

{

Invoice inv1;

Invoice inv2;

Invoice inv3;

inv1.setInvoiceNUMBER(1244);

inv1.setCustomer("Brown");

inv1.setBalanceDue(1000.00);

inv1.setTax();

inv1.displayInvoice();

inv2.setInvoiceNUMBER(77777);

inv2.setCustomer("Jenkins");

inv2.setBalanceDue(2000.00);

inv2.setTax();

inv2.displayInvoice();

inv3.setInvoiceNUMBER(888);

inv3.setCustomer("Russell");

inv3.setBalanceDue(3000.00);

inv3.setTax();

inv3.displayInvoice();

system("pause");

return 0;

}

Kindly check the output image below.

5 0
3 years ago
1. A truck leaves a stop sign and accelerates uniformly over a time of 5.21 seconds for a
Rufina [12.5K]

Answer:

1, is 21.11 meters per second.

110/5.21

Explanation:

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