Question

In a pentagon the measure of 4 angles are 2x°,3x°,4x°,5x° and the fifth angle measures 120°.find all the angles?​

Answer 1

$\huge{ \mathfrak{ \underline{ Answer} \: \: ✓ }}$

Angles of Pentagon are :

• 60°

• 90°

• 120°

• 150°

• 120°

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Answer 2

Given:

A pentagon with one of the angle measuring 120°

To find:

The measure of rest of the angles (2x,3x,4x&5x)

Solution:

We know that the measure of sum of all the angles in a pentagon = 540°

.°.

• 120°+2x+3x+4x+5x = 540°
• 120°+14x= 540°
• 120°-120°+14x = 540°-120°
• 14x = 420°
• x = 420°/14
• x=30

.°.

2x

$2x = 2 \times 30 = 60$

3x

$3x = 3 \times 30 = 90$

4x

$4x = 4 \times 30 = 120$

5x

$5x = 5 \times 30 = 150$

Hope it helps

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