Answer:
Attached please find response.
Step-by-step explanation:
We wish to find the area between the curves 2x+y2=8 and y=x.
Substituting y for x in the equation 2x+y2=8 yields
2y+y2y2+2y−8(y+4)(y−2)=8=0=0
so the line y=x intersects the parabola 2x+y2=8 at the points (−4,−4) and (2,2). Solving the equation 2x+y2=8 for x yields
x=4−12y2
From sketching the graphs of the parabola and the line, we see that the x-values on the parabola are at least those on the line when −4≤y≤2.
The answer is 580. when you multiply each unit by itself all you have to do is add and multiply again
Answer:
( , - )
Step-by-step explanation:
given the 2 equations
2x + 3y = - 4 → (1)
4x - y = 11 → (2)
Rearrange (2) expressing y in terms of x, that is
y = 4x - 11 → (3)
Substitute y = 4x - 11 into (1)
2x + 3(4x - 11) = - 4
2x + 12x - 33 = - 4
14x - 33 = - 4 ( add 33 to both sides )
14x = 29 ( divide both sides by 14 )
x =
Substitute this value into (3) for corresponding value of y
y = (4 × ) - 11 = - = - = -
solution is ( , - )
Answer:
3x(10+24)
Step-by-step explanation: