Basically you can graph a function, for example a parabola by following the step pattern 1,35...
If you take the "standard" parabola, y = x², which has it's vertex at the origin (0, 0), then:
<span>➊ one way you can use a "step pattern" is as follows: </span>
<span>Starting from the vertex as "the first point" ... </span>
<span>OVER 1 (right or left) from the vertex point, UP 1² = 1 from the vertex point </span>
<span>OVER 2 (right or left) from the vertex point, UP 2² = 4 from the vertex point </span>
<span>OVER 3 (right or left) from the vertex point, UP 3² = 9 from the vertex point </span>
<span>OVER 4 (right or left) from the vertex point, UP 4² = 16 from the vertex point </span>
<span>and so on ... </span>
<span>where the "UP" numbers are the sequence of "PERFECT SQUARE" numbers ... </span>
<span>but always counting from the VERTEX EACH time. </span>
<span>➋ another way you can use a "step pattern" is just as you were doing: </span>
<span>Starting with the vertex as "the first point" ... </span>
<span>over 1 (right or left) from the LAST point, up 1 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 3 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 5 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 7 from the LAST point </span>
<span>and so on ... </span>
<span>where the "UP" numbers are the sequence of "ODD" numbers ... </span>
<span>but always counting from the LAST point EACH time. </span>
<span>The reason why both Step Patterns Systems work is that set of PERFECT SQUARE numbers has the feature that the difference between consecutive members is the set of ODD numbers. </span>
<span>For your set of points, the vertex (and all the others) are simply "down 3" from the "standard places": </span>
<span>Standard {..., (-3, 9), (-2, 4), (-1, 1), (0, 0), (1, 1), (2, 4), (3, 9), ...} </span>
<span>shift ↓ 3 : {..., (-3, 6), (-2, 1), (-1, -2), (0, -3), (1,-2), (2, 1), (3, 6), ...} </span>
huh? pls explain more in comments
(5^3)^2 = 5^6
(3^-2)^-3= 3^-6
(7^4)^-2= 7^-14
I'm pretty sure
The answer would be 193 because first u multiply 19 and 10 and then subtract 5 which is 185 and finally add 8 which is 193.