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notka56 [123]
2 years ago
8

90 in Roman number is​

Mathematics
1 answer:
xenn [34]2 years ago
6 0

Answer:

90 in Roman number is XC

ans is : XC

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adoni [48]
What are the questions attach a pic plz
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3 years ago
Simplify 3+7x-(2+9x)
viva [34]

Answer:

-2x + 1

Step-by-step explanation:

3 + 7x - (2 + 9x)

Distribute the negative:

3 + 7x - 2 - 9x

Combine like terms:

-2x + 1

8 0
3 years ago
Ok so how can you tell if 2 angles are complementary, vertical, or supplementary? I don't know how to tell and I have pre-algebr
Ne4ueva [31]

Complementary angles are two angles that add up to 90°

Supplementary angles are two angles that add up to 180°

Vertical angles are two angles that are opposite of each other and are also congruent

7 0
2 years ago
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
3 years ago
GEOMETRY. 10 points :)
Lunna [17]
I think it's true. I'm so sorry if it's wrong
6 0
3 years ago
Read 2 more answers
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