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agasfer [191]
3 years ago
13

Please help me I’m desperate

Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer: y=2.75x+7.5, 10 miles

Step-by-step explanation:

Given

The company charges $2.75 per mile

The total charge is $29.50

Also, x represents the number of miles and y represents the total cost of the cab ride

Assume extra charge be c

for 8 miles, the charge is

\Rightarrow 29.50=2.75\times 8+c\\\Rightarrow c=\$7.5

The slope-intercept form of the information is

\Rightarrow y=2.75x+7.5

for $35 charge, miles covered

\Rightarrow 35=2.75x+7.5\\\Rightarrow 2.75=27.5\\\Rightarrow x=10\ \text{miles}

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jekas [21]
1.4 and there was a decrease in the slope.
4 0
3 years ago
PLZ HELP I DONT UNDERSTAND. Can someone explain this?
DENIUS [597]

Answer:

The equation for line m is;

5y = -3x + 36

The equation of line q is;

3y = 5x + 8

Step-by-step explanation:

Looking at the diagram, firstly, we can see that while n and m are perpendicular, q and m are parallel

We should also note that the the line m and q both share the point (2,6)

Let’s try and work to get the equation of the lines

For line n, we have two points (1,-1) and (4,4)

The slope here can be obtained by the equation;

m = y2-y1/x2-x1 = (4 -(-1))/(4-1) = 5/3

Now let’s get for equation m

When two lines are perpendicular, the product of their slopes is -1

Let’s say m1 is like n slope and m2 is like m slope

m1 * m2 = -1

5/3 * m2 = -1

m2 = -3/5

So the slope of line m is -3/5

To get the equation of line m, we use the point slope form

The point to consider is (2,6)

Hence;

y-y1 = m(x-x1)

y-6 = -3/5(x-2)

5(y-6) = -3(x-2)

5y -30 = -3x + 6

5y = -3x + 6 + 30

5y = -3x + 36

Since line n and q are also parallel, then their slopes are equal. Hence, the slope of line q is also 5/3

We use the point slope form to get the equation of line q

where m = 5/3 and point = (2,6)

Thus;

y-y1 = m(x-x1)

y-6 = 5/3(x-2)

3(y-6) = 5(x-2)

3y -18 = 5x -10

3y = 5x -10 + 18

3y = 5x + 8

6 0
3 years ago
The distribution of the amount of money in savings accounts for University of Alabama students has an average of 950 dollars and
Pavlova-9 [17]

Answer:

Approximately Normal, with a mean of 950 and a standard error of 158.11

Step-by-step explanation:

To solve this question, we need to understand the Central Limit Theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 950, \sigma = 1000

The sampling distribution of the sample mean amount of money in a savings account is

By the Central Limit Theorem, approximately normal with mean \mu = 950 and standard error s = \frac{1000}{\sqrt{40}} = 158.11

So the correct answer is:

Approximately Normal, with a mean of 950 and a standard error of 158.11

8 0
3 years ago
Find the first three output values of the fractal generating function . –3 + 2i, –34 – 129i, 8354 + 7526i –3 + 2i, 2 – 10i, 8354
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Fractal Generating Function, is

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=2-10 i

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So, First three output values of the fractal generating function are

1.⇒ -3+2i

2. ⇒ 2-10 i

3.⇒-38 i -99

8 0
3 years ago
What is the sample mean of 53, 29, 11, 13, 24
Marizza181 [45]
The mean is : 26

53 + 29 + 11 + 13 + 24 = 130

130 / 5 = 26
6 0
3 years ago
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