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aniked [119]
3 years ago
11

What is the quotient 10 ÷ (-5)? A) -2 B) 2 C) -12 D) 12

Mathematics
1 answer:
Degger [83]3 years ago
7 0
10 ÷(-5)= -2

The answer is A
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If x = 4, y = 2 and z = 1 then xz (4y - 2z) is: 861, 24, 46, or 40. Help please.
dybincka [34]
(4)(1) * (4(2)-2(1))
4 * (8-2)
4*6
24
8 0
3 years ago
Monica reads seven one half pages of a mystery book in nine minutes what is her average reading rate in pages per minute j
djverab [1.8K]

she can read a total of 0.83 pages a minute if she reads at the pace she was reading at because if you take the amount of pages she read (7.5) and you divide by the amout of minutes read (9) then you can see if she read at a constant rate she would read 0.83 pages a minute

6 0
3 years ago
How do you solve this? A and B
svp [43]
An adult polar bear is 8 times longer than a newborn.
Newborn= 12 1/2 ft
Multiply this by 8.
But first you have to turn the fraction
12 1/2 into an improper fraction. To do this you have to multiply the denominator, 2, by the whole number, 12, and add the numerator to the product, which totals to 25. The fraction is 25/2. (25/2 * 8/1)= 100 in simplified. 100 inches= 8 1/3 ft long
A= 8 1/3 ft long.
For B, you are dividing since you are trying to figure out the length of a newborn, not an adult polar bear. 9/8 turned into a mixed fraction is
1 1/8 ft. But, it asks in inches. 
B= 13 1/2 inches
I know this answer is very long but I hope it helps you understand better! 
:)

8 0
3 years ago
Read 2 more answers
At a local company, 15% of the employees are women. every day, 9% of them bring their lunch to work, while only 3% of the men br
fenix001 [56]

Answer:

a) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

b) 0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.

c) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Questions a/c:

Questions a and c are the same, so:

Event A: Brings lunch to work.

Event B: Is a woman.

Probability of a person bringing lunch to work:

9% of 15%(woman)

3% of 100 - 15 = 85%(man). So

P(A) = 0.09*0.15 + 0.03*0.85 = 0.039

Probability of a person bringing lunch to work and being a woman:

9% of 15%, so:

P(A \cap B) = 0.09*0.15

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.039} = 0.3462

0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

Question b:

Event A: Woman

Event B: Brings lunch

15% of the employees are women.

This means that P(A) = 0.15

Probability of a person bringing lunch to work and being a woman:

9% of 15%, so:

P(A \cap B) = 0.09*0.15

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.15} = 0.09

0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.

4 0
2 years ago
What is the following quotient?
seropon [69]

Answer:  Choice B) \frac{5\sqrt{11}+5\sqrt{3}}{8}\\\\

==========================================

Work Shown:

\frac{5}{\sqrt{11}-\sqrt{3}}\\\\\\\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{(\sqrt{11})^2-(\sqrt{3})^2}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{11-3}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{8}\\\\\\

This shows why choice B is the answer.

---------------

Explanation:

  • In the second step, I multiplied top and bottom by (\sqrt{11}+\sqrt{3})
  • This is so we can apply the difference of squares rule in step 3. The difference of squares rule is (x-y)(x+y) = x^2-y^2.
  • In step 4, the square roots cancel out with the squaring operation. The two operations are inverses of one another, which is why they cancel.

So in general, if the denominator is \sqrt{a}-\sqrt{b} and you want to rationalize the denominator, then you should multiply top and bottom by \sqrt{a}+\sqrt{b}. The same applies in reverse as well.

This leads to the denominator becoming (\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}) = (\sqrt{a})^2-(\sqrt{b})^2 = a-b

Keep in mind that a \ge 0 and b \ge 0

4 0
2 years ago
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