Answer:
The radius of the inflated spherical balloon is 45 millimeters.
Step-by-step explanation:
Volume of the spherical water balloon = 121,500 pi cubic millimeters
Let the radius of the balloon = r
Now, Volume of a Sphere = 
⇒
On solving for the value of r, we get:
![r^{3} = \frac{121,500\times 3}{4} = 91125\\ \implies r = \sqrt[3]{91125}](https://tex.z-dn.net/?f=r%5E%7B3%7D%20%20%3D%20%5Cfrac%7B121%2C500%5Ctimes%203%7D%7B4%7D%20%20%20%3D%2091125%5C%5C%20%5Cimplies%20%20r%20%20%3D%20%5Csqrt%5B3%5D%7B91125%7D)
or, r = 45 millimeter
Hence, the radius of the inflated spherical balloon is 45 millimeters.
55 degrees is the missing angle 90-35
Answer:
We'll use the following identities:
r = √(x2 + y2), from which we also have r2 = x2 + y2
y = r*sinθ
First, let's re-write your equation:
r = 8*sin(θ). Multiply both sides by r:
r2 = 8r sin(θ)
Now, we'll use substitute using the identities:
x2 + y2 = 8y
Re-arrange and complete the square:
x2 + y2 - 8y = 0
x2 + (y-4)2 - 16 = 0
x2 + (y-4)2 = 16
This represents a circle with center (0,4), and radius 4.
Step-by-step explanation:
sorry if it wrong
The answer is 52797. just line everything up vertically and subtract left to right, make sure you carry your remainders if any
Answer:
-18 + 6j
Step-by-step explanation:
you multiply 3 by -6 which is -18
then you multiply 3 by 2j which is 6j
