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Karo-lina-s [1.5K]
3 years ago
12

What is the solution to the following system?

Mathematics
2 answers:
Slav-nsk [51]3 years ago
7 0

Answer:

Therefore, x = 0 , y = 2 ,z = 5.

Step-by-step explanation:

Given  : Equations .

To find : What is the solution to the following system.

Solution : We have given that

x + 2y + z = 9 ------(1)

x -y + 3z = 13 ------(2)

2z = 10 ------(3)

On dividing by 2 both side on equation 3

z  = 5 .

Plug the value z = 5 in equation (1 )and (2).

x + 2y + 5 = 9

On subtracting both sides by 5

x + 2y = 9 -5

x + 2y = 4 -------equation(3)

From equation 2

x - y + 3 (5) = 13

x - y + 15 = 13

On subtracting both sides by 15

x -y = -2  ------equation (4)

On subtracting   equation(4) from equation(3).

x + 2y = 4

(-)x - ( +)y = - (+) 2

______________

0 + 3y =  6

On dividing by 3

y = 2.

Plug y = 2  in equation 3

x + 2( 2 ) = 4

x + 4 = 4.

On  subtracting both sides by 2.

x = 4 - 4

x  =  0 .

Therefore, x = 0 , y = 2 ,z = 5.

ycow [4]3 years ago
3 0
X=0, y=2, z=5. Hope this helps!
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Answer:

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Let <em>p</em> = proportion of business trip that were for  internal company visit.

It is provided that 19% responded that it was for an internal company visit, i.e.

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 \mu_{\hat p}=p

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\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Thus, the distribution of \hat p is N (<em>μ</em> = 0.19, <em>σ </em>= 0.013).

(a)

Compute the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (p' > 0.25) = P (Z > 4.62) = 0

*Use a <em>z</em>-table for the probability.

Thus, the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.

(b)

Compute the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (0.15 < p' < 0.20) = P (-3.08 < Z < 0.77)

                               = P (Z < 0.77) - P (Z < -3.08)

                               = 0.7794 - 0.0010

                               = 0.7784

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.7784.

(c)

Compute the proportion of <em>X</em> = 133  and <em>X</em> = 171 as follows:

p' = 133/950 = 0.14

p' = 171/950 = 0.18

Compute the value of P (0.14 < p' < 0.20) as follows:

P (0.14 < p' < 0.18) = P (-3.85< Z < -0.77)

                               = P (Z < -0.77) - P (Z < -3.85)

                               = 0.2206- 0.0001

                               = 0.2205

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.2205.

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