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BartSMP [9]
3 years ago
7

Question 2 (1 point)

Mathematics
1 answer:
BaLLatris [955]3 years ago
8 0

Answer:

All options are wrong.................

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In 2000, the population of Massachusetts
Zepler [3.9K]

Answer:

The population reaches 7 million people in the year 2032.

Step-by-step explanation:

We have that

f(x) = 6.3*(1.0032)^{x}

Using this model, find the year when the population reaches 7 million people.

This is x years after 2000, in which x is found when f(x) = 7. So

f(x) = 6.3*(1.0032)^{x}

7 = 6.3*(1.0032)^{x}

(1.0032)^{x} = \frac{7}{6.3}

(1.0032)^{x} = 1.11

We have to following logarithm rule

\log{a^{x}} = x\log{a}

So we apply log to both sides of the equality

\log{(1.0032)^{x}} = \log{1.11}

x\log{1.0032} = \log{1.11}

x = \frac{\log{1.11}}{\log{1.0032}}

x = 32.66

2000 + 32.66 = 2032

The population reaches 7 million people in the year 2032.

3 0
3 years ago
What is 5 x 5 x 5 + 290?
cupoosta [38]

Answer:

415

Step-by-step explanation:

okay so this is how i do the math in my head

so, 5 x 5 x 5 + 290

5*5= 25

25*5 = 125

125+ 290= 415

7 0
3 years ago
Read 2 more answers
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
A population of 42 fruit flies has increased
Alex777 [14]
Multiply 42 times 150 percent or 42×1.5 which would be 63
7 0
3 years ago
Undefined terms needed to define a line segment
Alenkinab [10]
Is a point line and <span>plane</span>
7 0
4 years ago
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