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gregori [183]
2 years ago
13

Need help asap this is really important

Mathematics
1 answer:
nadya68 [22]2 years ago
5 0

Answer:

y = \frac{4}{3}x -7

Step-by-step explanation:

Use the points (9, 5) and (6, 1) to identify the slope of the graph

m = \frac{y^2-y^1}{x^2-x^1}

m = \frac{1-5}{6-9}

m = \frac{-4}{-3}

m = \frac{4}{3}

The y-intercept is -7 because -7 touches y axis causing it to be the y-intercept

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If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
HELP ASAP I WILL GIV YOU BRAINLIST! Jim ran 200 meters in 30.4 seconds. Mac ran 100 meters in 30.4 seconds. Who ran faster?
statuscvo [17]

Jim ran faster than Mac.

3 0
3 years ago
Which of the sets of ordered pairs represents a function
rjkz [21]

4 neither of them are functions because the x repeats itself

4 0
3 years ago
Read 2 more answers
Evaluate the expression 2ab 3+ 6a 3 - 4ab2 when a=2 and b=4.<br> a.176<br> b.180<br> c.215<br> d.216
Tom [10]
The first step for solving this expression is to insert what a and b stand for into the expression. This will change the expression to the following:
2(2)(4)³ + 6(2)³ - 4(2)(4)²
Now we can start solving this by factoring the expression
2(2 × 4³ + 3 × 2³ - 4 × 4²)
Write 4³ in exponential form with a base of 2.
2(2 × 2^{6} + 3 × 2³ - 4 × 4²)
Calculate the product of -4 × 4².
2(2 × 2^{6} + 3 × 2³ -4³)
Now write 4³ in exponential form with a base of 2.
2(2 × 2^{6} + 3 × 2³ -2^{6})
Collect the like terms with a base of 2.
2(2^{6} + 3 × 2³)
Evaluate the power of 2³.
2(2^{6} + 3 × 8)
Evaluate the power of 2^{6}.
2(64 + 3 × 8)
Multiply the numbers.
2(64 + 24)
Add the numbers in the parenthesis.
2 × 88
Multiply the numbers together to find your final answer.
176
This means that the correct answer to your question is option A.
Let me know if you have any further questions.
:)
5 0
3 years ago
Solve 19.9 = 9 y - 8.<br> Y=
Savatey [412]
The answer would be y = 3.1

19.9 + 8 = 9y

27.9 = 9y

27.9/9 = y

3.1 = y

y = 3.1.
3 0
3 years ago
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