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Sergio039 [100]

3 years ago

6

A kickball has a radius of 7 inches. Calculate the volume of the kickball. Use 3.14 to for . Volume of a sphere can be calculate

d by the formula: V=4/3 r^3 (round to the nearest whole number)

1 answer:

ValentinkaMS [17]3 years ago

6 0

Answer:

V = 205 in^3 to the nearest whole number

Step-by-step explanation:

V = 4/3 π r^3

Plugging in the given information:

V = 4/3 * 3.14 * 7^2

V = 205.147.

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Help with this question, please!

uranmaximum [27]

Answer:

52 ft

Step-by-step explanation:

For each chord, the product of segment lengths is a constant. We can find that constant as the product of the segment lengths of the bisected chord:

(24 ft)·(24 ft) = 576 ft^2

Then the missing segment length (DX) of the diameter chord is ...

DX·(36 ft) = 576 ft^2

DX = (576 ft^2)/(36 ft) = 16 ft

So, the total length of the diameter chord is ...

DX +XL = 16 ft + 36 ft

DL = 52 ft

_____

We know DL is a diameter because the perpendicular bisector of any chord intersects the center of the circle.

5 0

3 years ago

3. Write out the prime factor of the following numbers.<br> a. 15<br> b. 21<br> C. 38<br> d. 42

Minchanka [31]

Answer:

The prime factors of 15 are: 1,3,5,15

The prime factors of 21 are: 1,3,7,21

The prime factors of 38 are: 1,3,13,39

The prime factor of 42 is : 1,2,3,6,7,14,21,42

6 0

3 years ago

I NEED THE ANSWER ASAP

denpristay [2]

Answer:

-3119

Step-by-step explanation:

(-5)^2 - 2 x (-9) + 6

-5^2 - 2 x -9 + 6

-3125 - 2 x -9 + 6

-3125 - -18 + 6

-3125 - -6

-3119

I hope this helps :)

6 0

3 years ago

A new bridge structure requires triangles that are in a ratio of 1:1. If AC = 2x + 10 and EC = 4x − 18, find the distance betwee

gavmur [86]

Answer: The required distance between the top and bottom of the bridge is 76 feet.

Step-by-step explanation: Given that a new bridge structure requires triangles that are in a ratio of 1:1.

AC = 2x + 10 and EC = 4x − 18.

We are to find the distance between the top and bottom of the bridge, in feet.

Since the two triangles ACB and DCE are in the ratio 1 : 1, so their corresponding sides are also in the ratio 1 : 1.

The sides AC and EC are corresponding to each other, so we must have

$AC:EC=1:1\\\\\Rightarrow \dfrac{AC}{EC}=\dfrac{1}{1}\\\\\Rightarrow AC=EC\\\\\Rightarrow 2x+10=4x-18\\\\\Rightarrow 4x-2x=10+18\\\\\Rightarrow 2x=28\\\\\Rightarrow x=\dfrac{28}{2}\\\\\Rightarrow x=14.$

Therefore, the distance between the top and bottom of the bridge is

$EA\\\\=EC+AC\\\\=4x-18+2x+10\\\\=6x-8=6\times14-8\\\\=84-8\\\\=76~\textup{feet}.$

Thus, the required distance between the top and bottom of the bridge is 76 feet.

6 0

4 years ago

What is the Perfect square of 44

nataly862011 [7]

2<span>√ ̅11is going to be your answer.

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5 0

3 years ago