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Sergio039 [100]

3 years ago

6

A kickball has a radius of 7 inches. Calculate the volume of the kickball. Use 3.14 to for . Volume of a sphere can be calculate

d by the formula: V=4/3 r^3 (round to the nearest whole number)

1 answer:

ValentinkaMS [17]3 years ago

6 0

Answer:

V = 205 in^3 to the nearest whole number

Step-by-step explanation:

V = 4/3 π r^3

Plugging in the given information:

V = 4/3 * 3.14 * 7^2

V = 205.147.

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl

Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0

4 years ago

*SUPER EASY POINTS**COORDINATES RELATED*

andreev551 [17]

Answer:

8. (0,-2)

9. (-2,1)

Step-by-step explanation:

Lucy's house is at (1,1)

Down means in the y coordinate , left means negative x

Down 3 means subtract 3 from y

left 1 means subtract 3 from x

(1-1, 1-3)

(0,-2)

9. Lucy is at (1,1)

3 units to the left

left means subtract 3 from x

(1-3, 1)

(-2,1)

4 0

3 years ago

Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}

sashaice [31]

Hey there!

Assuming you meant

$5r^2 - 12 = 68$

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to $add$ by $12$ on each of your sides

$5r^2 -12 +12 \\ \\ 68 + 12$

$5r^2 = 5r^2 \\ \\ 68 + 12 = 80$

We get: $5r^2 =80$

Now, we have $divide$ by $5$ on each of your sides

$\frac{5r^2}{5} = \frac{80}{5}$

$\frac{80}{5} = 16$

We get: $r^2 = 16$

$r =$ ± $\sqrt{16}$

Therefore , your answer is: $r =$ ± $4$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

3 0

3 years ago

Solve the equation x2 + 7x = 30.

Law Incorporation [45]

Answer:

2*7=14+6=30 points plz

5 0

3 years ago

6a+(8b+2a)=6a+(2a+8b)=0 <br><br>please help me solve this

solniwko [45]

<span>Simplifying (6a + -8b)(6a + 8b) = 0 Multiply (6a + -8b) * (6a + 8b) (6a * (6a + 8b) + -8b * (6a + 8b)) = 0 ((6a * 6a + 8b * 6a) + -8b * (6a + 8b)) = 0 Reorder the terms: ((48ab + 36a2) + -8b * (6a + 8b)) = 0 ((48ab + 36a2) + -8b * (6a + 8b)) = 0 (48ab + 36a2 + (6a * -8b + 8b * -8b)) = 0 (48ab + 36a2 + (-48ab + -64b2)) = 0 Reorder the terms: (48ab + -48ab + 36a2 + -64b2) = 0 Combine like terms: 48ab + -48ab = 0 (0 + 36a2 + -64b2) = 0 (36a2 + -64b2) = 0 Solving 36a2 + -64b2 = 0 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '64b2' to each side of the equation. 36a2 + -64b2 + 64b2 = 0 + 64b2 Combine like terms: -64b2 + 64b2 = 0 36a2 + 0 = 0 + 64b2 36a2 = 0 + 64b2 Remove the zero: 36a2 = 64b2 Divide each side by '36'. a2 = 1.777777778b2 Simplifying a2 = 1.777777778b2 Take the square root of each side: a = {-1.333333333b, 1.333333333b}</span>

4 0

3 years ago