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Sergio039 [100]

3 years ago

6

A kickball has a radius of 7 inches. Calculate the volume of the kickball. Use 3.14 to for . Volume of a sphere can be calculate

d by the formula: V=4/3 r^3 (round to the nearest whole number)

1 answer:

ValentinkaMS [17]3 years ago

6 0

Answer:

V = 205 in^3 to the nearest whole number

Step-by-step explanation:

V = 4/3 π r^3

Plugging in the given information:

V = 4/3 * 3.14 * 7^2

V = 205.147.

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nalin [4]

If hugo has 1400 and on the 2 month it is c

3 0

2 years ago

Can I have help solving for x?:))

zvonat [6]

Answer:

24.8

Step-by-step explanation:

We will have to use trigonometry here to find the value of x. The first thing we can see is that we need to work out the hypotenuse. We need to chose whether to use Sin, Cos or Tan. We do that by look at the sides .

→ 'x' is the hypotenuse

→ 12 is opposite

→ The adjacent is the side that doesn't have a numerical value to we look for a formula triangle without adjacent in it

Tan = Opposite ÷ Adjacent

Sin = Opposite ÷ Hypotenuse

Cos = Adjacent ÷ Hypotenuse

We can see the Sin formula has no adjacent in it so we use that formula. However we want to work out the hypotenuse so we have to rearrange the sin formula to get hypotenuse as the subject so

Sin = Opposite ÷ Hypotenuse

Hypotenuse = Opposite ÷ Sin

→ Let's substitute in the values

Hypotenuse = 12 ÷ Sin(29)

Hypotenuse = 24.7519841

So the value of x is 24.8 to 1 decimal place

6 0

3 years ago

Read 2 more answers

HURRRRRRYYYYYYY 1 QUESTION EXPERTS/ACE HELP QUICK!!!!!

MakcuM [25]

I believe the answer is C.

4 0

3 years ago

In a mathematics class, half of the students scored 79 on an achievement test. With the exception of a few students

Yakvenalex [24]

In this situation, you have:
The mode is 79 (that’s the most common number).
The median is 78.5 (the middle value or the average of the two middle values, since there is an even number of test scores).
The mean is less than both of those, as it was brought down by the few scores of 49.

The means the mean will be less than median.

Answer: C

3 0

3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

6 0

3 years ago