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cluponka [151]
3 years ago
5

Can you help me solve this? Thanks!

Mathematics
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

135/2

Step-by-step explanation:

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Write a function rule for the area of a triangle whose base is 4 ft more than the height. What is the area of the triangle when
solong [7]

Answer:

A) Area as function of H ,

     F'(a) = 2 +H

B) Area of triangle with height 6ft = 30 ft²      

Step-by-step explanation:

Given as for a triangle ,

Let the height of triangle = H ft

And base = 4 ft + H ft

Now area of triangle = \frac{1}{2} × height  × base

                          F (a) =  \frac{1}{2} × H × ( 4ft + H ft)

Or,                      F (a) =  \frac{1}{2} × ( 4H + H² )

Now,   here Area is function of height ,

So ,                    F'(a) = \frac{1}{2}(4 + 2H)

Hence Area as function of H ,

                          F'(a) = 2 +H

Now For height = 6 ft

Area of triangle = \frac{1}{2} × height × base

                          = \frac{1}{2} × H × ( 4ft + H ft)

                          = \frac{1}{2} × ( 4H + H² )

                          =  \frac{1}{2} × ( 24 + 36 )

                          = \frac{1}{2} × ( 60 )

                          = 30 ft²

Hence Area of triangle with height 6ft = 30 ft²      Answer

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