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zalisa [80]
3 years ago
9

Find the area of the parallelogram

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

multiply the base by the height

Step-by-step explanation:

23x13

weqwewe [10]3 years ago
3 0

Answer:

299 feet

Step-by-step explanation:

Okay so the cut off triangle you can move to the right side to make it a perfect rectangle. Find tha area.

13 x 23 = 299 feet

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An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,
butalik [34]

Answer:

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

s=\sqrt{r_{A}^{2}+r_{B}^{2}}

Rate of change of such distance can be found by the deriving the expression in terms of time:

\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }

Where \frac{dr_{A}}{dt} = 500\,\frac{mi}{h} and \frac{dr_{B}}{dt} = 550\,\frac{mi}{h}, respectively. Distances of each airliner at 2:30 PM are:

r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi

r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi

The rate of change is:

\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

6 0
3 years ago
Find the area of a circle, in terms of pi, if the radius is 20 ft.
arlik [135]
Area of circle= π·r² so, π·20²= π·400≡ 1256.637061
8 0
3 years ago
write the equation for the nth term of the sequence and then find the value of the 24th term: 4, 13, 22, 31, ...
julia-pushkina [17]

Answer :

nth term

an = a1 + (n-1) d

an = 4 + (9-1) 9

an = 4 + (8)9

an = 4 + 72

an = 82

24th term

an = 4 + (24-1) 9

an = 4 + (23) 9

an = 4 + 207

an = 211 is the answer

Hope it helped

4 0
3 years ago
A hiker travels 45 degrees north of east for 30 km. What is his NORTH (or y) displacement component? Round your answer and inclu
miv72 [106K]

consider X-axis along the east-west direction and north-south direction along Y-axis

A = magnitude of distance traveled by hiker in north-east direction = 30 kilometer

θ = angle of direction of displacement of the hiker relative to x-axis or east direction = 45 degree counterclockwise

A' = component of distance traveled by the hiker along the east direction.

Since the angle is given with the x-axis, the Sin provides the component in Y-direction. hence

Using the equation

A' = A Sinθ

Inserting the values

A' = (30) Sin45

A' = 21.2 km

8 0
3 years ago
All numbers bigger than five, or at most negative one
Kisachek [45]

Answer:

Hi there!

Your answer is:

-1 >=x>5

This can be broken down to:

x <= -1

x>5

Which fits your requirements!

6 0
4 years ago
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