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Phantasy [73]
3 years ago
9

Which answer represents the series in sigma notation? −7+(−2)+3+8+13 ∑j=15(5j−12) ∑j=15(−8j+1) ∑j=15−5(15)j−1 ∑j=155j−1

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

∑j=15(5j−12)

Step-by-step explanation:

For j = 1 up to j = 5

j = 1

(5j - 12) = (5(1) - 12) = 5 - 12 = - 7

j = 2

(5j - 12) = (5(2) - 12) = 10 - 12 = - 2

j = 3

(5j - 12) = (5(3) - 12) = 15 - 12 = 3

j = 4

(5j - 12) = (5(4) - 12) = 20 - 12 = 8

j = 5

(5j - 12) = (5(5) - 12) = 25 - 12 = 13

(-7 + (-2) + 3 + 8 + 13)

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Answer:

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Step-by-step explanation:

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3 years ago
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Suppose the rate of type II diabetes in 40- to 59-year-olds is 7% among Caucasians, 10% among African-Americans, 12% among Hispa
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Answer:

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

Step-by-step explanation:

We have these following rates of type II diabetes:

7% among Caucasians

10% among African-Americans

12% among Hispanics

5% among Asian-Americans.

The ethnic distribution of Houston is:

30% Caucasian

25% African-American

40% Hispanic

5% Asian-American

What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?

P = P_{1} + P_{2} + P_{3} + P_{4}

P_{1} is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.

P_{1} = 0.07*0.30 = 0.021

P_{2} is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.

P_{2} = 0.1*0.25 = 0.0215

P_{3} is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.

P_{3} = 0.12*0.40 = 0.048

P_{4} is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.

P_{3} = 0.05*0.05 = 0.0025

P = P_{1} + P_{2} + P_{3} + P_{4} = 0.021 + 0.0215 + 0.048 + 0.0025 = 0.093

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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