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Fynjy0 [20]
3 years ago
15

How do I solve 15=3p/6 ?

Mathematics
2 answers:
valina [46]3 years ago
7 0
Given : 15 = 3p/6

=> 15 x 6 = 3p

=> 90 = 3p

=> p =90/3

=> p = 30

Hope this helps you :)
DerKrebs [107]3 years ago
4 0
I uploaded on how to do it there are pictures. Answer is p=30

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A line's y -intercept is 10,and its slope is 9 . What is its equation in slope-intercept form?
LenaWriter [7]

Answer:

y = 9x + 10

Step-by-step explanation:

y = mx + b

Here, m is slope and b is y-intercept

y = 9x + 10

3 0
3 years ago
Which equation could be used to find the height of the flagpole
Sauron [17]
X = height of pole (in meters)

With respect to the 50 degree angle, the side x is the opposite leg. It is the leg furthest from the reference angle. The hypotenuse is 5 meters. 

The trig function sine ties together the opposite and hypotenuse

sin(angle) = opposite/hypotenuse
sin(50) = x/5
5*sin(50) = x .... multiply both sides by 5
x = 5*sin(50)

------------------

Since x = 5*sin(50) isn't listed as an answer choice, let's try using cosine. We can't use it right away because we don't know the adjacent side. What we can do is change the reference angle. The missing angle of the triangle is 90-50 = 40 degrees. Let's make the 40 degree angle the reference angle

So x is now the adjacent side with respect to the 40 degree reference angle. The hypotenuse is always the longest side. The hypotenuse stays at 5.

cos(angle) = adjacent/hypotenuse
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This expression is listed. The answer is choice B

4 0
3 years ago
What is the first step in solving 5v+9=−51
diamong [38]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Which of the following points is a solution of y > Ixl + 5?
Step2247 [10]

Answer:

B. (1,7)

Step-by-step explanation:

We can substitute the x and y values of each coordinate into the inequality and test if they work.

Let's start with A, 5 being y and 0 being x .

5 > |0|+5\\5> 0+5\\5 > 5

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Let's try B, 1 being x and 7 being y.

7 > |1| + 5\\7 > 1 + 5\\7 > 6

7 IS greater than 6, so B. (1,7) does work for this inequality!

Let's do C for fun, when 7 is x and 1 is y.

1 > |7| + 5\\1>7+5\\1>12

1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.

Therefore B. (1,7) works for the inequality of y > |x|+5.

Hope this helped!

7 0
3 years ago
Please help me with this word problem.
koban [17]
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