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BartSMP [9]
3 years ago
11

The length of a rectangular garden is 3 m greater than the width.the area of the garden is 70 m^2. Find the dimensions of the ga

rden
Mathematics
2 answers:
erastova [34]3 years ago
4 0

Answer:

Step-by-step explanation:

A = L x W

so you know that the length is 3m longer than the width, so you could use a formula to represent that

w = L + 3

you then substitute the second equation into the first to solve for L

70 = L x (l +3)

70 = L^2 + 3l

you could then rearrange the formula and solve for l using the quadratic formula  

0 = L^2 + 3l - 70

l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)

l = -3 +- (square root 9 + 280) / 2

l = -3 +- (square root 289) / 2

l = -3 +- 17 / 2

then you solve for the two separate roots

l = -3 + 17 /2

l = 14 / 2

l = 7

or  

l = -3 - 17 / 2

l = -20 / 2

l = -10

since a length cannot be negative, this root is not viable. therefore l = 7

to solve for w you would use

w = l + 3

w = 7 + 3

w = 10  

hope this helps. :)))

aleksandr82 [10.1K]3 years ago
3 0
Yes it’s crazy
Cause my dad came back with the milk
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Find cube root of 175616 ??​
Tpy6a [65]

Answer:

56

Step-by-step explanation:

Cube root of 175616 by prime factorization method is 56

Solution:

To find cube root of 175616 by prime factorization method

A number that must be multiplied by itself three times to equal a given number is called cube root

Prime factorization method:

Prime factorization is a number written as the product of all its prime factors.

In order of finding cube root by prime factorization we use the following steps:

Step I : Obtain the given number

Step II : Resolve it into prime factors.

Step III : Group the factors in 3 in such a way that each number of the group is same

Step IV : Take one factor from each group

Step V : Find the product of the factors obtained in step IV. This product is the required cube root

Prime factorization of 175616:

\text{ prime factors of 175616 } = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 prime factors of 175616 =2×2×2×2×2×2×2×2×2×7×7×7

Thus we get,

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7}

3

175616

=

3

2×2×2×2×2×2×2×2×2×7×7×7

Make the groups of 3 of equal numbers

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{2 \times 2 \times 2 \times } \times \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{7 \times 7 \times 7}

3

175616

=

3

2×2×2

×

3

2×2×2×

×

3

2×2×2

×

3

7×7×7

So there are 4 equal groups. So from that group take one factor out

\sqrt[3]{175616} = 2 \times 2 \times 2 \times 7 = 56

3

175616

=2×2×2×7=56

Thus Cube root of 175616 by prime factorization method is 56

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