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skelet666 [1.2K]
3 years ago
9

I need help on number 5 and 6 Help Please As soon as possible I really need your help!!!

Mathematics
2 answers:
Margarita [4]3 years ago
6 0
Use a ruler to find your measure
Nastasia [14]3 years ago
5 0
Use a ruler to find the measure of each line and make sure you look at the inches
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in a direct variation, y=10when x=5 Write a direct variation equation that shows the relationship between x and y​
loris [4]

Answer:

y=2x

Step-by-step explanation:

(10)=2(5)

4 0
2 years ago
A rectangle measures 12 cm by 4 cm what is the area
Maslowich
In order to find the area you have to multiply length x width 
In this case our length and width are 12cm and 4cm 
So lets multiply those. :P
12 x 4 = 48 cm

Your area = 48cm²

Good Luck! :)
6 0
3 years ago
Find the equation of the line that passes through the following two points: (3, -7) and (7, 2)
Wittaler [7]

Answer:

y=\frac{9}{4}x-\frac{55}{4}

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: \frac{y2-y1}{x2-x1}

Given points: (3, -7), (7, 2)

(3, -7) = (x1, y1)

(7, 2) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

\frac{2-(-7)}{7-3}

Simplify:

2 - (-7) = 2 + 7 = 9

7 - 3 = 4

\frac{9}{4}

The slope is \frac{9}{4}.

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:

2=\frac{9}{4}(7)+b

2=\frac{63}{4}+b

-\frac{55}{4} =b

The y-intercept is -\frac{55}{4}.

Now that we know the slope and the y-intercept, we can write the equation:

y=\frac{9}{4}x-\frac{55}{4}

6 0
3 years ago
a bag of potting soil costs $3 less than a flower pot. Ike paid $41 for 3 flower pots and 5 bags of soil. how much does one bag
Arada [10]
Cost of bag of soil = x-3 where x is the price of a flower pot
41=3x + 5(x-3)
41=3x + 5x -15
41=8x -15
41+15=8x
56=8x
56÷8=x
$7.00=x
5 0
3 years ago
What are the domain, range, and asymptote of h(x) = (0.5)x – 9?
Rzqust [24]

Let's solve for h

hx = 0.5x - 9

Step 1: Divide both sides by x.

hx/x = 0.5x - 9/ x

Answer = h = 0.5x - 9/ x

8 0
3 years ago
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