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Gennadij [26K]
3 years ago
12

Will give brainlyist if quick

Mathematics
1 answer:
Feliz [49]3 years ago
7 0

Answer:

B)

Step-by-step explanation:

slope = 1/2(rise/run)

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Charlie has a piece of toast that has cream cheese on one side, and he dropped it once. One time, it landed with the cream chees
Nina [5.8K]
What the heck who puts cream cheese on toast and im pretty sure the answer would be D
8 0
3 years ago
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A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

m=\frac{y_2-y_1}{x_2-x_1 }

<u>Slope  of AB</u>

m_{AB}=\frac{8-5}{1--5}

\Rightarrow m_{AB}=\frac{8-5}{1+5}

\Rightarrow m_{AB}=\frac{3}{6}

\Rightarrow m_{AB}=\frac{1}{2}


<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

\Rightarrow m_{BC}=\frac{-6}{3}

\Rightarrow m_{BC}=-2

<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-4}{-6}

\Rightarrow m_{CD}=\frac{2}{3}

<u>Slope of AD</u>

m_{AD}=\frac{-2-5}{-2--5}

\Rightarrow m_{AD}=\frac{-2-5}{-2+5}

\Rightarrow m_{AD}=\frac{-7}{3}

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




6 0
3 years ago
If your good at math pls help me I’ll mark brainliest
pentagon [3]

Answer:

it's answer is A x = 3

x³ = 27

x³ = 3³

x = 3

Hope it will help :)

7 0
3 years ago
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What is equivalent to the equation to 1/4 (8 + 6z + 12) ?
Fed [463]
1/4 (8 + 6z + 12) 

------------------------------------------------------------
Combine like terms :
------------------------------------------------------------
1/4 (6z + 20)

------------------------------------------------------------
Apply distributive property :
------------------------------------------------------------
1/4(6z) + 1/4(20)
3/2z + 5

------------------------------------------------------------
Answer: 3/2z + 5
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7 0
3 years ago
How is a function<br> different than a<br> relation?
Nastasia [14]
<h3><u>Explanation</u></h3>
  • Difference between relation and function.

Relation and Function both are same except for one thing.

Relation can have repetitive domain while Function cannot. We can say that Function is a relation without repetitive domain.

<u>Example</u><u> </u><u>of</u><u> </u><u>Relation</u>

{(1,1),(1,3),(2,5),(2,6),(3,46),(3,90)}

This is a relation because there are same and repetitive domain.

<u>Example</u><u> </u><u>of</u><u> </u><u>Function</u>

{(1,1),(2,4),(3,9),(4,16),(5,25),(6,36),(7,49)}

This can be classified as relation as well but relation that is function. We can say that function is a subset of relation. Remember that functions are relations that don't have repetitive domain while relations that are not function (or just relations) can have repetitive or same domain.

<u>Graph</u><u> </u><u>of</u><u> </u><u>Relation</u><u> </u><u>and</u><u> </u><u>Function</u>

Relations can have graphs along with Functions. The problem is you might not see set of ordered pairs but graph instead.

How can we tell if the graph is a function or just only relation? The answer is to do line test.

  1. First we draw a vertical line.
  2. See if the line intercepts the graph just one point or more than one.

If the graph intercepts only one point then it is a function. Otherwise, no.

5 0
3 years ago
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