Question

Next, the team wants to explore how it can change the steepness of the curved pit. Identify how the graph of each equation compares with the graph of the parent quadratic equation, y=x^2. Drag the equations to the correct location on the chart. Not all equations will be used

Answer 1

$y = \frac 14x^2$ is less steep than the parent quadratic equation, while $y = 2x^2$ is steeper than the parent quadratic equation

How to determine the equations

The parent equation of a quadratic equation is represented as:

$y = x^2$

For a function to be steeper or less steep than the parent function must be stretched or compressed by a factor k

So, we have:

$y = (kx)^2$

If k is greater than 1, then the function would be steeper; else, the function would be less steep.

Assume k = 2, we have:

$y = (2x)^2$

$y = 2x^2$

Assume k = 1/2, we have:

$y = (\frac 12x)^2$

$y = \frac 14x^2$

Hence, $y = \frac 14x^2$ is less steep than the parent quadratic equation, while $y = 2x^2$ is steeper than the parent quadratic equation

Read more about quadratic equations at:

brainly.com/question/11631534