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2 years ago

5

HELP NOW PLEASE ASAP!!

2 answers:

algol [13]2 years ago

4 0

Answer:

The answer is D, your welcome

Sever21 [200]2 years ago

3 0

Answer:

The 2nd answer is correct.

Step-by-step explanation:

Between x = - 4 and x = - 1 the function is represented by a straight line (and is therefore lineair). Moreover, the value of y increases when moving to the right (and therefore the function is increasing).

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Please show how to compute these values. Thank you.

alekssr [168]

Answer: ln ( 40) *100

Step-by-step explanation:

Substituting 140 in the equation,

140 = 100 + e^(.01q)

40 = e^(.01q)

Take the natural log of bot hsides

ln ( 40) = .01q

q= ln ( 40 ) * 100

6 0

3 years ago

Dentify the percent, amount, and base in this problem. 75% of what number is 30?

anastassius [24]

Answer:

40

Step-by-step explanation:

This is essentially just (4/3), or $\frac{3}{4}^{-1}$ . (4/3)*30 = 40, so our answer must be 40. Just to check, taking 75 percent of 40, we indeed get 30!

7 0

3 years ago

Read 2 more answers

Given f(x) and g(x) = k·f(x), use the graph to determine the value of k

k0ka [10]

Answer:

$k=-5$

Step-by-step explanation:

If we observe the graph carefully there are two on each of the graphs highlighted at x=-2.The functions take the following values at that x.

$f(-2)=2$

$g(-2)=-10$

given the condition

$g(x)=k*f(x)$

put $x=-2$

we get . $-10=k*2$

$k=-5$

4 0

3 years ago

:)))) solve the following by factorizing: x^2-2x=120

stepladder [879]

Answer:

Step-by-step explanation:

$x^2 - 2x = 120\\x^2 - 2x - 120 = 0$

We have to find the factors of 120 that can either add up to or have a difference of 2.

The factors of 120 are:

$\pm 1, 120, 2, 60, 3, 40, 4, 30, 5, 44, 6, 20, 8, 15, 10, 12...$

The difference of 10 and 12 is 2. In the equation, since the 2 is negative, the larger number must be subtracted, so the factorized form is:

$(x+10)(x-12)$

3 0

3 years ago

Assume that the population proportion is 0.56. Compute the standard error of the proportion, σp, for sample sizes of 100, 200, 5

Aliun [14]

Answer:

Standard errors are 0.049, 0.035, 0.022, and 0.016.

Step-by-step explanation:

The given value of population proportion (P) = 0.56

Given sample sizes (n ) 100, 200, 500, and 1000.

Now standard error is required to calculate.

Use the below formula to find standard error.

When sample size is n = 100

$\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{100}} =0.049$

When sample size is n = 200

$\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{200}} = 0.035$

When sample size is n = 500

$\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{500}} =0.022$

When sample size is n = 1000

$\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{1000}} = 0.016$

4 0

3 years ago