1. Hugo scored 18 points in a recent basketball game, which was 5 points fewer than Toby scored. Write an equation for this situ
ation and find how many points Toby scored.
A. 18 + 5 = t, Toby scored 23 points
B. 18 = t + 5, Toby scored 23 points
C. 18 = t – 5, Toby scored 23 points
D. 18 = t + 5, Toby scored 13 points
2. Which of the following equations is modeled by the graph?
A. a = 50 + t
B. a = 50t
C. a = 5t
D. a = 10t
The graph to question number 2 is in the picture below.
A. 18 + 5 = t, Toby scored 23 points
B. 18 = t + 5, Toby scored 23 points
C. 18 = t – 5, Toby scored 23 points
D. 18 = t + 5, Toby scored 13 points
2. Which of the following equations is modeled by the graph?
A. a = 50 + t
B. a = 50t
C. a = 5t
D. a = 10t
The graph to question number 2 is in the picture below.
1 answer:
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Answer:
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher
Step-by-step explanation:
Data provided in the question:
sample size, n = 103
Mean temperature, μ = 98.3
°
Standard deviation, σ = 0.73
Degrees of freedom, df = n - 1 = 102
Now,
For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]
Therefore,
CI =
Thus,
Lower limit of CI =
or
Lower limit of CI =
or
Lower limit of CI = 98.11
and,
Upper limit of CI =
or
Upper limit of CI =
or
Upper limit of CI = 98.49
Hence,
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F