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kow [346]
2 years ago
13

Kylee made 1 3 4 quarts of hot tea to serve to her best friends. She filled as many mugs as she could and had a small portion of

tea left over. The mugs each held 2 7 quart of tea. How many quarts of tea did she have left over?
Mathematics
1 answer:
kolezko [41]2 years ago
7 0

Answer:

1/8 quart

Step-by-step explanation:

STEPS TO DETERMINING THE ANSWER

Divide the total quarts of hot tea by the size of the mug. the remainder of the division is the leftover

1\frac{3}{4} ÷ \frac{2}{7}

\frac{7}{4} ÷ \frac{2}{7}

\frac{7}{4} ×\frac{7}{2} = \frac{49}{8} = 6\frac{1}{8}

6 cups would be filled and 1/8 quart would be left over

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Answer:

2/3

Step-by-step explanation:

2/5=0.4 and 4/7=0.571428

0.57<0.571428

---------------------------

2/3=0.6667

which is greater than or equal to 4/7

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X+5-8x=26<br> Solve for x
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What is the factorization of 729^15+1000?
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Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
2 years ago
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