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-BARSIC- [3]
3 years ago
12

I really need help. It would mean a lot ❤️!

Mathematics
1 answer:
crimeas [40]3 years ago
4 0

Answer: The domain has to be x and the range y. But for independent and dependent variable I can't help. So srry. The picture doesn't show the work. Have a nice day :)

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Ion
erik [133]

Answer: It is being dilated by a scale factor of 1/3.

Step-by-step explanation:

The pre-image has the coordinates (0,0) (6,0) (6,-3) and (0,-3) and a transformation has been applied to it to get the coordinates of the image to be (0,0) (2,0) (2,-1) ( 0,-1)

Looking at the coordinates we can see that to get from 6 to 2 you will have to multiply by  1/3 and to  get from -3 to -1 you will have to multiply by 1/3.

This means that pre-image was dilated  by a scale factor of 1/3.

8 0
4 years ago
While walking through a fictional forest, you encounter three trolls guarding a bridge. Each is either a knight, who always tell
AlexFokin [52]

Answer:

Troll 1: Knight

Troll 2: Knave

Troll 3: Knight

Step-by-step explanation:

Troll 3's statement must be true because if they can only be knights or knaves, unless all of them are knaves, at least one must be a knight. Thus, Troll 3 is a knight.

If Troll 2 is a knight, then Troll 1 is knave, but if that were the case Troll 1's statement would be true, and since knaves do not tell the truth, this assumption is incorrect.

If Troll 2 is a knave, Troll 1 is a knight and his statement can be disregarded since it is conditioned to the possibility of him being a knave.

Therefore, Trolls 1 and 3 are knights and Troll 2 is a knave.

7 0
4 years ago
If 5 liters of a solution are 20% acid, how much of the solution is acid?
UkoKoshka [18]
Acid is 0.2*5 = 5* 1/5 = 1 liter. We should multiple mass and concentration (in this conditions). So, 1 liter.
5 0
4 years ago
A jelly bean is 5 grams heavy and a tree is 20 meters tall
Finger [1]
9.945*10^30 Kg - 1.7901*10^32 Kg
This is on average what the mass of a black hole.

8 0
3 years ago
Θ is in Quadrant III and cos^2 0= 1/4
pychu [463]
I think you mean to say \cos^2\theta=\dfrac14. If \theta is in the third quadrant, then \sin\theta and \cos\theta. Recall that


\sin^2\theta+\cos^2\theta=1\implies\sin\theta=\pm\sqrt{1-\cos^2\theta}

We expect \sin\theta to be negative, so we take the negative root. We end up with

\sin\theta=-\sqrt{1-\dfrac14}=-\dfrac{\sqrt3}2

We also know to expect \cos\theta, so

\cos\theta=\pm\sqrt{\dfrac14}\implies\cos\theta=-\dfrac12


By definition, we have

\cot\theta=\dfrac{\cos\theta}{\sin\theta}

and so

\cot\theta=\dfrac{-\frac12}{-\frac{\sqrt3}2}=\dfrac1{\sqrt3}
7 0
3 years ago
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