Answer:
Step-by-step explanation:
we can say the angle is also +45° going in the clock wise direction. so take Tan(45)= 1
Cot(45) = 1
b/c Tan(45) = Sin(45) /Cos(45) = (
/2) / (/2) ofc that's just 1
b/c Cot(45) = Cos(45) / Sin(45) , which is the same as above 1
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Step-by-step explanation:
y |X(the sign for protionality) 1/√x
y = 7 when x = 36
y = k/√x
7 = k/√36
7 = k / 6 cross multiply
k = 7×6
k = 42
find y when x is 4
y = 42/√x
y = 42/√4
y = 42/2
y = 21
X(x+5)=234
x^2 +5x=234
x^2+5x-234=0
Factor:
x^2+5x-234
(x-13)(x+18)
the integers are 13 and 18.
