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3 years ago

Write a quadratic equation ax²+ bx + C = 0, whose coefficients are a =-9, b = 0, c = -2

Mathematics

1 answer:

aksik [14]3 years ago

8 0

Let's write -9 where we see A:

Let's write 0 where we see B:

(Since B = 0, when it is multiplied by x, it becomes 0 again)

Let's write -2 where we see C:

Now we can move on to solving our equation:)

Let's put the known and the unknown on different sides:

(-2 goes to the opposite side positively)

(it goes as a division because it is in the case of multiplying -9 across)

 

I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.

Please do not report:(

I hope I got it right, I'm trying to improve my English a little :)

<h3>Greetings from Turkey:)</h3>

<h3>#XBadeX</h3>

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3 years ago

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ankoles [38]

$\bf ~~~~~~ \textit{Simple Interest Earned}
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I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$1575\\
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r=rate\to r\%\to \frac{r}{100}\\
t=years\to &7
\end{cases}
\\\\\\
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3 years ago

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

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