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3 years ago

Abcd is a parallelogram. Photo provided

Mathematics

1 answer:

Savatey [412]3 years ago

8 0

The correct answer is A. 120 ft squared because you must multiply the height times the width which comes to 120.

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A video game has five stages. If Will beat 4/5 of the stages, what percent of the game has he finished

fiasKO [112]

Answer:

75%

Step-by-step explanation:

1 = 10%

2 = 25%

3 = 50%

4 = 75%

5 = 100%

5 0

2 years ago

Lucas is offered either 15% or $21 off his total shopping bill. how much would have to be spent to make the 15% option the best

vladimir1956 [14]

Let the total bill be x. We have:
<span>0.15x > 21 <-- Since 15% is 0.15 using inequality calc. x </span>>$140

4 0

3 years ago

Determine if the pair of triangles are similar or not.

dedylja [7]

Answer: SAS

Step-by-step explanation:

5 0

3 years ago

Please help!! Thanks in advance :)

Alisiya [41]

Answer:

180 plants

Step-by-step explanation:

the area of a right triangle is: ab/2

side a = 8

side b = 15

8 x 15 = 120

120/2 = 60

Michael wants 3 plants for every square yard (multiply by 3)

60 x 3 = 180

7 0

3 years ago

Read 2 more answers

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

4 0

3 years ago