All categories

2 years ago

If the lengths of two sides of a triangle are 3 and 12, which could be the length of the third side?

Mathematics

1 answer:

Ierofanga [76]2 years ago

6 0

Answer: 1st is if it’s 2 legs second is if it’s a leg and hypotenuse

Step-by-step explanation:

You might be interested in

What is 1365in Egyptian numeral

anygoal [31]

Answer:

I used an Egyptian numeral converter.

Step-by-step explanation:

8 0

3 years ago

Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.

Blizzard [7]

Answer:

The answer is

$y = 3$

$y = - 4$

Step-by-step explanation:

We must find a solution where

$\frac{6}{y + 1} + \frac{y}{y - 2} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

$\frac{6}{y + 1} \times \frac{y - 2}{y - 2} + \frac{y}{y - 2} \times \frac{y + 1}{y + 1}$

Which equals

$\frac{6y - 12}{(y -2) (y + 1)} + \frac{ {y}^{2} + y }{(y - 2)(y + 1)}$

Add the fractions

$\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Simplify the right side by multiplying the fraction

$\frac{6y}{(y + 1)(y + 2)}$

Set both fractions equal to each other

$\frac{6y}{(y + 1)(y - 2)} = \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}$

Since the denomiator are equal, we must set the numerator equal to each other

$6y = {y}^{2} + 7y - 12$

$= {y}^{2} + y - 12$

$(y + 4)(y - 3)$

$y = - 4$

$y = 3$

6 0

2 years ago

Read 2 more answers

27.6 inches of rain fell over a 100 day period. What was the average amount of rain that fell per day?

egoroff_w [7]

27.6/100 = 0.276
The average amount of rain that fell is 0.276 inches per day.

3 0

2 years ago

Which of these WAS NOT one of Huey Long's campaign promises?

kumpel [21]

I think the answer is D.

3 0

2 years ago

Anyone know the answer to any of these.

skad [1K]

A is c=75 B is a=120 C is b= square root of 75 and D= square root of 245

7 0

3 years ago