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user100 [1]
3 years ago
6

Guided Practice

Mathematics
1 answer:
zysi [14]3 years ago
4 0

Answer:

D.

πr2(2h)pi r squared left parenthesis 2 h right parenthesis

Step-by-step explanation:

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For your equation n = 0 l = -5/2
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Choose the answer to complete each statement
NeTakaya

Answer:

1. The slope of the line is 7/3

2. y intercept is -3

3. y= 7/3x -3

Step-by-step explanation:

To find the slope of the line you use the equation y2-y1/x2-x1

y2 and y1 are y coordinates of the 2 coordinates on the same line that you want to find the slope of and the same with x2 and x1

The y-intercept is the point where the line crosses the y axis and x= 0

the equation of a line is y= mx+b

m= slope

b= y intercept

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3 years ago
Saras bike weighs 2.03 kilograms . If 1 kilogram is 2.2 pounds, how much many pounds is saras bike
Olin [163]

Answer:

4.5 pounds

Step-by-step explanation:

2.2X2.03=4.466(I rounded to the nearest tenth if that helps)

5 0
3 years ago
Free poinnttssssssssssssssss and yourr welcomeee
DerKrebs [107]

Answer:

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Step-by-step explanation:

have a good day

5 0
3 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
3 years ago
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