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Papessa [141]
3 years ago
13

The director of a marching band asks the band members to line up in rows of four, but one is left over. Then she tries to line t

hem up in rows of six, but three are left over. Finally, she tries to line them up in rows of seven, but four are left over.
The band has fewer than $100$ members.
Mathematics
2 answers:
Olin [163]3 years ago
5 0

Answer:

There are 81 band members.  :-)

Step-by-step explanation:

4 rows of 20 = 80 ... with one left over   = 80 + 1  (81)

6 rows of 13 = 78 ... with three left over = 78 + 3  (81)

7 rows of 11 = 77 ... with four left over   = 77 + 4  (81)

Julli [10]3 years ago
4 0
81 band members is left that answer ^^^^^^^^^^^%
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Describe how you know that (8+9)+3 is equivalent to 8+(9+3). What is the benefit to using this property
NISA [10]

Answer:

Associative property of addition

Step-by-step explanation:

The associative property of addition is as follows :

a+(b+c) = (a+b)+c

We have,

a = 8, b = 9 and c = 3

So,

Using above property,

(8+9)+3 = 8+(9+3)

20 = 20

Hence, this is the required solution.

7 0
3 years ago
I NEED HELP PLEASE SOMEONE HELP ME
sasho [114]

Answer:

2nd option is the correct answer

Step-by-step explanation:

3 times a number decreased by 6 is - 2

4 0
3 years ago
If y varies directly with x, and y= 10 when x = 4, find y when x = 10.​
mixer [17]

Answer:

17

Step-by-step explanation:

bc

6 0
3 years ago
Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
3 years ago
HELP! Brainliest to first correct answer with work shown!
juin [17]

Answer:

Step-by-step explanation:

A.  f(8) = 11

B.  f(x) = 7, so x = 3

7 0
3 years ago
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