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2 years ago

Area of composite shapes Find the area of the shape shown below.

Mathematics

2 answers:

RoseWind [281]2 years ago

6 0

Answer: 18

Step-by-step explanation:

Here you have two triangles and a square. Or what's also called a trapezoid.

$A=\frac{a+b}{2}h$

a = shorter side = 3

b = longer side = 9

h = height = 3

$A=\frac{3+9}{2}(3)$

$A=\frac{12}{2}(3)$

$A=6*3\\A=18$

Salsk061 [2.6K]2 years ago

4 0

Answer:

18units

Step-by-step explanation:

3+9=12

12/2=6

6*3=18

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2 years ago

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Answer:

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2 years ago

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il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

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6 0

2 years ago

Rosa is converting a unit of measure in one system to a unit of measure in another system (1, 760yd)/(1mj) * (0.914m)/(1yd) * (1

Murljashka [212]

Answer:

The statement about Rosa's calculations that is true is (0.914m)/(1yd).

Step-by-step explanation:

The ratio of meter (m) to yard (yd) is 0.914 : 1.

Therefore, the conversion factor is 0.914 m/1 yd

6 0

2 years ago

Read 2 more answers

The diameter of a circle has length 12. The center is at*(-5, 2). Give the equation

labwork [276]

Answer:

Equation of the circle is : $x^{2} + 10x + y^{2} -4y -7 =0$

Step-by-step explanation:

Let us consider the image attached in the answer area.

The center<em> O</em> has the co-ordinates i.e. <em>(-5,2)</em> and the diameter given is <em>12 units</em>.

We know that radius is half of diameter.

$\text{Radius = }\dfrac{\text{Diameter}}{2}$

$\text{Radius = }\dfrac{12}{2}\\\Rightarrow \text{Radius = 6units}$

The equation for circle given the center and radius, can be represented as:

$(x-a)^{2}+ (y-b)^{2} = r^{2}$

Where <em>(a,b)</em> is the co-ordinate of center and <em>r</em> is the radius.

Let us consider the following formula:

$(p+q)^2 = p^{2}+ q^{2} +2pq\\(p-q)^2 = p^{2}+ q^{2} -2pq$

$(x-(-5))^{2}+ (y-2)^{2} = 6^{2}\\\Rightarrow (x+5)^{2}+ (y-2)^{2} = 36\\\Rightarrow x^{2} + 25 + 10x +y^{2} + 4-4y=36\\\Rightarrow x^{2} + 10x +y^{2} -4y-7=0$

Hence, Equation of the circle is : $x^{2} + 10x + y^{2} -4y -7 =0$

4 0

2 years ago