How do I solve problem 7?

Mathematics

1 answer:

miskamm [114]3 years ago

3 0

Answer:

16ᵗʰ Term of the sequence is 1010

Step-by-step explanation:

7.)

Here,

First Term = a₁ = 5

Common Difference = d = 67

Now, For 16ᵗʰ term, n = 16

aₙ = a + (n - 1)d

a₁₆ = 5 + (16 - 1) 67

a₁₆ = 5 + 15 × 67

a₁₆ = 5 + 1005

a₁₆ = 1010

Thus, 16ᵗʰ Term of the sequence is 1010

-TheUnknownScientist

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If Pentagon ABCDE was dilated to create Pentagon A'B'C'DE', what rule was used?

svetlana [45]

Answer:

B $(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)$

Step-by-step explanation:

Dilations

Given a point A(x,y) and a scale factor k the dilated image of A, called A' is calculated as A'=(kx,ky), assuming the same scale factor is applied in both axes.

The pentagon ABCDE was dilated to create pentagon A'B'C'D'E'. To find the dilaton rule used, we must find two clear points where the coordinates of both axes can be easily read from the graph.

Point C(-2,0) maps to C'(-5,0). This gives us the scale factor for the x-axis of -5/(-2)= 5/2.

The y-coordinate of E is 2 and the y-coordinate of E' is 5. This gives us the same scale factor for the y-axis of 5/2.

Thus, the rule to dilate the pentagon is:

B $\mathbf{(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)}$