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Ira Lisetskai [31]
2 years ago
7

The table shows survey results for 500 people, in which they were asked if they had a pierced ear. If one person is selected

SAT
1 answer:
Mkey [24]2 years ago
4 0

Answer:

d 10

Explanation:

cz thats alot of people

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AP courses is the correct answer.

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Why might you choose to filter a list or table instead of simply sorting it?.
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I would choose a coordinate table. And list them as (x,y)
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you are moving across town. doing your research, you find that the average rate of a moving company is $250 per hour for a movin
iragen [17]

Based on the information given, the marginal cost of the price that should be paid is $250 per hour.

This is an incomplete information. From the complete information, the number of moving crew will be gotten where the marginal cost is equal to the marginal benefit and this will be at the 4th hour. Therefore, the <em>marginal cost</em> and benefit equal $250.

Therefore, one should hire movers for 4 hours. Therefore, based on the information given, the consumer surplus will be:

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In conclusion, the total consumer surplus for hiring a crew for<u> 4 hours</u> will be<u> $1220.</u>

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brainly.com/question/3200587

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Based on current birth and death rates, by 2050 Europe’s population will be larger than it is today. Please select the best answ
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A tortoise and a hare engage in a race. A tortoise can run with a speed of 0. 15 m/s. A hare can run 25 times as fast as the tor
Nonamiya [84]

Let D be the total length of the race, and T the time it takes for the tortoise to finish it. Then

D = (0.15 m/s) T

Let t be the time after the start of the race when the hare decides to take a nap. In this time, the tortoise travels a distance

(0.15 m/s) t

and the hare travels

25 (0.15 m/s) t = (3.75 m/s) t

For the next 5.0 min = 300 s, the tortoise keeps moving and covers a distance of

(0.15 m/s) (300 s) = 45 m

while the hare covers no distance.

After these 300 seconds, the remaining time for the tortoise to complete the race is (T - t - 300 s). In this same time, the hare loses the race by 35 cm = 0.35 m, so overall it has covered a total distance of

(3.75 m/s) t + 0 (300 s) + (3.75 m/s) (T - t - 300 s) = D - 0.35 m

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(3.75 m/s) t + 0 + (3.75 m/s) T - (3.75 m/s) t - 1125 m = D - 0.35 m

(3.75  m/s) T - 1125 m = D - 0.35 m

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(a) It also follows that the race has a total length of

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