Frequency = 1/time period = 1/0.05 = 20s^-1.
<span>The volume of a cube is given by s^3. So the volume of this block is 3cm x 3cm x3 cm = 27 cm^3. density = mass/volume =27 g / 27 cm^3 = 1 g/cm^3.</span>
That was a lucky pick.
Twice each each lunar month, all year long, whenever the Moon,
Earth and Sun are aligned, the gravitational pull of the sun adds
to that of the moon causing maximum tides.
This is the setup at both New Moon and Full Moon. It doesn't matter
whether the Sun and Moon are both on the same side of the Earth,
or one on each side. As long as all three bodies are lined up, we
get the biggest tides.
These are called "spring tides", when there is the greatest difference
between high and low tide.
At First Quarter and Third Quarter, when the sun, Earth, and Moon form a
right angle, there is the least difference between high and low tide. Then
they're called "neap tides".
If hunter fires a bullet 2 degree below the horizontal
then the components of its speed is given as


so here initial speed of the bullet is not zero but have some magnitude in downwards direction
While the other bullet is dropped downwards so its initial speed will be zero
So here we can say

so if we use above equation we will find that the bullet that is shot at 2 degree below the horizontal will reach the ground first as its speed is more
Answer:
Ein: 2.75*10^-3 N/C
Explanation:
The induced electric field can be calculated by using the following path integral:

Where:
dl: diferencial of circumference of the ring
circumference of the ring = 2πr = 2π(5.00/2)=15.70cm = 0.157 m
ФB: magnetic flux = AB (A: area of the loop = πr^2 = 1.96*10^-3 m^2)
The electric field is always parallel to the dl vector. Then you have:

Next, you take into account that the area of the ring is constant and that dB/dt = - 0.220T/s. Thus, you obtain:

hence, the induced electric field is 2.75*10^-3 N/C